Explanation:
Molarity is defined as number of moles per liter of solution.
Mathematically, molarity = 
It is given that molarity is 0.0800 M and volume is 50.00 mL or 0.05 L.
molarity = 
0.0800 M = 
no. of moles = 1.6 mol
Therefore, molar mass of cupric sulfate pentahydrate is 249.68 g/mol. So, calculate the mass as follows.
No. of moles = 
mass in grams = 
= 
= 399.488 g
Thus, we can conclude that 399.488 g of cupric sulfate pentahydrate are needed to prepare 50.00 mL of 0.0800M CuSO4× 5H2O.
Answer:
False
Explanation:
While we do know that A. Leeuwenhoek used a simple microscope that consisted of only 1 lens, Hooke used a compound microscope. Although, after trying a compound microscope, Hooke found out that it strained his eyes and continued to use a simple microscope for his <em>Micrographia</em>.
Thus, we can say that the (compound) microscopes used today are different than the (simple) microscope used by Hooke and Leeuwenhoek.
Answer:
It's a type of chemical bond that emerges because of electrostatic force between electrons and positive metal charges.
Explanation:
I don't know if this is what you are looking for but i don't mind if you copy it.
Answer:
C
Explanation:
The reason why C is true is because this species of plant requires certain things to survive, and without said requirements they will die. Hence, the animal that is unable to compete will die and be eliminated from the ecosystem. Hope that helps!
The mass of Ce(NO3)₄ that will be needed to create the solution was 24.16 g (in grams).
<h3>
What exactly is the solution?</h3>
A homogenous mixture with one or even more solutes that have been dissolved in the solvent is known as a solution. The material that a solute dissolves in to create a homogenous mixture is known as a solvent. To create a homogenous mixture, a component must dissolve in a solvent.
<h3>
What is an illustration of a solution?</h3>
One nanometer or smaller particles are referred to as a solution in a homogeneous mixture made up of two or more components. There are many different types of solutions, including sugar and salt solutions and fizzy water. Each component shows up as a different phase in a solution.
<h3>
Briefing:</h3>
Mole of Ce(NO₃)₄ = 0.06225 mole
Molar of Ce(NO₃)₄ = 140.12 + 4[14 + (16×3)]
= 140.12 + 4[14 + 48]
= 140.12 + 4[62]
= 140.12 + 248
= 388.12 g/mol
Mass of Ce(NO₃)₄ = 0.06225 × 388.12
Mass of Ce(NO₃)₄ = 24.16 g
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