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Alinara [238K]
3 years ago
12

Which correctly describes a cross section of the cube below? Check all that apply.

Mathematics
2 answers:
dmitriy555 [2]3 years ago
7 0

Answer:

A cross section parallel to the base is a square measuring 4 cm by 4 cm.

A cross section perpendicular to the base through the midpoints of opposite sides is a square measuring 4 cm by 4 cm.

A cross section that passes through the entire bottom front edge and the entire top back edge is a rectangle measuring 4 cm by greater than 4 cm.

Step-by-step explanation:

Cross sections parallel and Perpendicular to the base are squares 4 × 4

The diagonal cross section will be a rectangle with base 4 and height

sqrt(4² + 4²) = 4sqrt(2) > 4

wolverine [178]3 years ago
4 0

Answer:

B,D, and E

Step-by-step explanation:

A cross section parallel to the base is a rectangle measuring 4 cm by greater than 4 cm.

A cross section perpendicular to the base through the midpoints of opposite sides is a square measuring 4 cm by 4 cm.

A cross section that passes through the entire bottom front edge and the entire top back edge is a rectangle measuring 4 cm by greater than 4 cm.

I have come to help your needs! meep :3

ur welcome peeps and have a wonderful day!

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Answer:

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Step-by-step explanation:

We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.

Also, a random sample of 25 specimens is selected.

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(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z < 2.06) = 0.98030

 P(X bar <= 2.65) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3)  = 0.98030 - 0.5 = 0.4803 .

                                                                             

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