Given,

We can use L'Hopital's Rule to get,
![\lim_{x}^{a}\dfrac{2}{3-\sqrt[3]{x}}](https://tex.z-dn.net/?f=%5Clim_%7Bx%7D%5E%7Ba%7D%5Cdfrac%7B2%7D%7B3-%5Csqrt%5B3%5D%7Bx%7D%7D)
Now plug in a,
![\boxed{\dfrac{2}{3-\sqrt[3]{a}}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cdfrac%7B2%7D%7B3-%5Csqrt%5B3%5D%7Ba%7D%7D%7D)
Hope this helps.
r3t40
Step-by-step explanation:
Let the painting's width be w inches and length be l inches.
w + 6 = 2l
w = 2l - 6 --(1)
2w + 2l = 84 --(2)
sub (1) into (2):
2(2l - 6) + 2l = 84
2l - 6 + l = 42
3l = 48
l = 16
when l = 16, w = 2(16) - 6 = 26
area of painting = lw = 16 x 26 = 416square inches
Therefore, only statements 1, 3 and 5 are true
Topic: Algebraic equations + Simultaneous linear equations
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Answer:
6 units
Step-by-step explanation:
F(-3) = 8
Plug -3 into x and just solve it.