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3 years ago

Which integer is closest to 0 on the number line?

Mathematics

1 answer:

IrinaVladis [17]3 years ago

8 0

An integer is close to zero if it is "small".

By small, we mean that it is small in absolute value. In fact, for any given distance $d$ , there are two integers that are $d$ units away from zero: $d$ and $-d$ .

So, for example, -6 is close to zero than 8, because -6 is six units away from zero, while 8 is eight units away from zero.

So, the answer is B, -8, because it is 8 units away from zero. The other options A, C and D are, respectively, 12, 10 and 14 units away from zero.

You might be interested in

Is perpendicular to . How many 90° angles are formed by the intersection?

xxTIMURxx [149]

4, there are 4 equal angles

3 0

4 years ago

Solve. 2x - 1 = 7 a) x = 2 b) x = 3 c) x = 4 d) x = 5.

svlad2 [7]

C) x=4 is the answer
2*4-1=7
8-1=7

8 0

3 years ago

Which pairs are like terms in expression 2/5y + 1/5x - 0.2y - 6 + (-2)

Gelneren [198K]

The pair of like terms are:

$\frac{2}{5}y \text{ and } -0.2y$

Solution:

Given expression is:

$\frac{2}{5}y + \frac{1}{5}x -0.2y-6+(-2)$

We have to find the pairs that are like terms in the given expression

Like terms means that, terms that have same varibale but different ( or same ) coefficients

Here in the given expression "x" and "y" are the two variables present

Arrange the like terms

$\frac{2}{5}y-0.2y+\frac{1}{5}x-6+(-2)$

So here the first two terms has same varibale "y" but different coefficients. So they form a pair of like terms

"x" is present only once . There is no other term with variable "x"

6 and -2 are constants

So the pair of like terms are: $\frac{2}{5}y \text{ and } -0.2y$

3 0

3 years ago

There are approximately 7.5×10^18 grains of sand on earth. There are approximately 7×10^27 atoms in a average human body. Are th

grandymaker [24]

There are more atoms in average human body than grains of sand on Earth. We can know it because we can see that atoms' number (7 * 10^27) is being multiplied by much greater number (with 9 zeros more) than grain's number (7.5 * 10^18).

4 0

3 years ago

In right triangle ΔABC (m∠C = 90°), point P is the intersection of the angle bisectors of the acute angles. The distance from P

arlik [135]

Answer:

28 inches

Step-by-step explanation:

The point of intersection of the angle bisectors is the incenter. It is the center of a circle tangent to the three sides of the triangle. The circle has radius 2.

In the attached figure, we have labeled the points of tangency D, E, and F. We know that CE and CF are both of length 2, and we know that the points of tangency are the same distance from an external point where the tangents intersect. That means DA = FA and DB = EB.

The perimeter of the triangle is ...

P = DA +DB +FA +EB +CF +CE

Using the above relations, this can be written as ...

P = DA +DB +DA +DB +CF +CE = 2(DA +DB) +2(CE)

We are told that AB is 12 inches, so DA +DB = 12 inches. We also know that CE = 2 inches, so the perimeter is ...

P = 2(12 in) + 2(2 in) = 28 in

The perimeter of triangle ABC is 28 inches.

4 0

3 years ago