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Readme [11.4K]
3 years ago
7

During the first year, ABC's stock price starts at $ \$100 $ and increases $ 100\% $. During the second year, its stock price go

es down $ 25\% $ from its price at the end of the first year. What is the price of the stock, in dollars, at the end of the second year?
Mathematics
2 answers:
Artemon [7]3 years ago
6 0

Answer:

Step-by-step explanation:

During the first year, ABC's stock price starts at $100 and increases by 100%. This means that the amount by which the stock increased would be

100/100 × 100 = $100

The new price of the stock would be 100 + 100 = $200

During the second year, its stock price goes down 25% from its price at the end of the first year. This means that the amount by which the stock reduced is

25/100 × 200 = 0.25 × 200 = $50

Therefore, the price of the stock, in dollars, at the end of the second year is

200 - 50 = $150

Reil [10]3 years ago
6 0

Answer:

150

Step-by-step explanation:

In the first year, the price doubles. This happens because 100% of 100 is 100, so 100+100 is 200, which is also 100 multiplied by 2. 25/100 which is 25%, multiplied by 200, is 50. So the answer is 200-50 which equals 150.

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The first- and second-year enrollment values for a technical school are shown in the table below: Enrollment at a Technical Scho
lyudmila [28]

Answer:

  • <u><em>The solution to f(x) = s(x) is x = 2012. </em></u>

Explanation:

<u>Rewrite the table and the choices for better understanding:</u>

<em>Enrollment at a Technical School </em>

Year (x)       First Year f(x)      Second Year s(x)

2009                  785                        756

2010                   740                        785

2011                    690                        710

2012                   732                         732

2013                   781                          755

Which of the following statements is true based on the data in the table?

  • The solution to f(x) = s(x) is x = 2012.
  • The solution to f(x) = s(x) is x = 732.
  • The solution to f(x) = s(x) is x = 2011.
  • The solution to f(x) = s(x) is x = 710.

<h2>Solution</h2>

The question requires to find which of the options represents the solution to f(x) = s(x).

That means that you must find the year (value of x) for which the two functions, the enrollment the first year, f(x), and the enrollment the second year s(x), are equal.

The table shows that the values of f(x) and s(x) are equal to 732 (students enrolled) in the year 2012,<em> x = 2012. </em>

Thus, the correct choice is the third one:

  • The solution to f(x) = s(x) is x = 2012.
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