So this is how we are going to solve for the given problem above.
Given that x = number of large boxes
and 120-x = number of small boxes.
So here is the solution:
50x + (120-x)20 = 4050
50x + 2400 - 20x = 4050
30x + 2400 = 4050
30x = 4050 - 2400
30x = 1650 <<divide both sides by 30
x = 55.
Therefore, there are 55 large boxes
120 - x = small boxes
120 - 55 = 65 small boxes.
Hope this is the answer that you are looking for.
Let me know if you need more help next time!
Answer:
length of fence =201 ft
Step-by-step explanation:
radius including path=28+4=32 ft
circumference=2πr=2×3.14×32≈201 ft.
Scale factor is always (new/original)
so it depends which rectangle came first. if it started as large and was dilated to the smaller one, then the ratio is (.5/2.5) which simplifies to 1/5 or 0.2.
We are given
Angles α and β are angles in standard position
and
α terminates in Quadrant II
β terminates in Quadrant I
and we have
we can use triangle and find cos(α)
we get
and we have
we can draw triangle
now, we can use formula
now, we can plug values
now, we can simplify it
...............Answer
Answer:
1. (1, 2)
2. (-5, 7)
3. (-6, -5)
4. (0, -3)
Step-by-step explanation:
(1 - 4) Explanation:
If we're asked to move to the right, make the x-coordinate a positive number.
If we're asked to move to the left, make the x-coordinate a negative number.
If we're asked to move upwards, make the y-coordinate a positive number.
If we're asked to move downwards, make the y-coordinate a negative number.
