Write the equation of the line that passes through 7, 0 and is parallel to y = -3x + 4
1 answer:
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Hello,
(tg(x))'=1/cos²(x)
(arcsin(x))'=1/√(1-x²)
cos²(arcsin(x))=1-sin²(arcsin(x))=1-x²
(tg(x))'=1/cos²(x)
(arcsin(x))'=1/√(1-x²)
cos²(arcsin(x))=1-sin²(arcsin(x))=1-x²
Answer:
I can only help you with Part C and E as these two are the ones I am able to answer.
Part C: slopes are not the same
Part E: 195 yards
Step-by-step explanation:
Part C:
Part E: The slope of the line follows a linear pattern; therefore, find the equation for the line by calculating the slope and plugging in a point.
Slope:
y2-y1/x2-x1; (9, 105) (8,115)
(115-105)/(8-9) = -10; the slope is -10, now solve for the equation of the line.
y=mx+b; plug in the point (9,105)
105 = -10(9) +b
105 = -90 +b, add 90 to both sides
195 = b; rewrite the equation;
y=-10x+195; x stands for the iron, plug in 0 for x;
y=-10(0)+195
y=195 yards.
