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eduard
4 years ago
13

you must exert a force of 4.5 N on a book to slide it across a table. If you do 2.7 j of work in the process, how far have you m

oved the book?
Physics
2 answers:
motikmotik4 years ago
7 0

             Work  =  (force) x (distance)

      2.7 Joules  =  (4.5 N) x (distance)

         distance  =  2.7 J / 4.5 N 

                       =   0.6 meter           
wolverine [178]4 years ago
5 0
Work done (energy) = force * distance

So: distance = work done / force

= 2.7 / 4.5

= 0.6m
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What potential difference is needed to stop an electron that has an initial velocity v=6.0
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To find the potential difference needed to decelerate an electron to rest, set the work done on the electron equal to its kinetic energy:

W = KE

Substitute W = ΔVq and KE = 0.5mv²

ΔVq = 0.5mv²

Given values:

q = 1.6×10⁻¹⁹C

m = 9.11×10⁻³¹kg

v = 6.0m/s

Plug in the given values and solve for ΔV

ΔV×1.6×10⁻¹⁹ = 0.5×9.11×10⁻³¹×6.0²

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A 12 kg crate, resting on a horizontal surface, is pulled by a force that is applied at an angle of 30° above the horizontal. F
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Answer:

70.6N

Explanation:

We are given that

Mass of crate=12 kg

\theta=30^{\circ}

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Force along vertical direction

Fsin\theta+mg=N..(2)

Using equation(2) in equation (1)

Fcos\theta=\mu(Fsin\theta+mg)

Fcos\theta=\mu Fsin\theta+\mu mg

\mu mg=Fcos\theta-\mu Fsin\theta=F(cos\theta-\mu sin\theta)

F=\frac{\mu mg}{cos\theta-\mu sin\theta}

Substitute the values then we get

F=\frac{2\times 0.40\times 9.8}{cos 30-0.40sin 30}

F=70.6N

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3 years ago
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satela [25.4K]

Answer:

They are found in the Hydrosphere

Explanation:

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