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3 years ago

What diameter is the sun by the scale used? a0 mm

Physics

2 answers:

tino4ka555 [31]3 years ago

7 0

The answer is kilometers.

ehidna [41]3 years ago

7 0

6gms thats what I think so yes umm thats it pretty much

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Vascular plants can be divided into three categories. These categories are

Evgesh-ka [11]

I believe the answer here is <span>C).seedless, seed (nonflowering), and seed (flowering).</span><span>
</span>

6 0

3 years ago

Suppose that a car traveling to the west (-x direction) begins to slow down as it approaches a traffic light. Which statement co

dalvyx [7]

Answer:

Its acceleration is positive

Explanation:

As the car is moving in the negative x-direction than after applying brake then there will be a decrease in the acceleration but in the opposite direction.

As decreasing acceleration consider to be negative but the car is moving in negative direction which means increasing acceleration is negative by sign convention but by applying brake acceleration decrease but in opposite direction than it will give positive value of acceleration.

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3 years ago

The power in an electrical circuit is given by the equation P = I2R, where I is the current flowing through the circuit and R is

kiruha [24]

Answer:

Explanation: Here we have given a direct equation . There for no need to worry .

P = I²×R

P = (12)² ×100

P = 14400W = 14.4 kW

For second one

P = I² ×R

200 = I²×150

I = √200/150

I = 1.15 A

5 0

2 years ago

Given vectors D (3.00 m, 315 degrees wrt x-axis) and E (4.50 m, 53.0 degrees wrt x-axis), find the resultant R= D + E. (a) Write

fomenos

Answer:

(a) $\vec{R}= 4.83\ m\ \hat{i}+1.47\ m\ \hat{j}$

(b) (5.05 m, 16.93 degrees wrt x-axis)

Explanation:

Given:

$\vec{D}$ = (3.00 m, 315 degrees wrt x-axis)
$\vec{E}$ = (4.50 m, 53.0 degrees wrt x-axis)

Let us first fond out vector D and E in their rectangular form.

$\vec{D} = (3\cos 315^\circ\ \hat{i}+3\sin 315^\circ\ \hat{j})\ m\\\Rightarrow \vec{D} = (2.12\ \hat{i}-2.12\ \hat{j})\ m\\$

Similarly,

$\vec{E} = (4.5\cos 53^\circ\ \hat{i}+4.5\sin 53^\circ\ \hat{j})\ m\\\Rightarrow \vec{D} = (2.71\ \hat{i}+3.59\ \hat{j})\ m\\\because \vec{R}=\vec{D}+\vec{E}\\\therefore \vec{R} = (2.12\ \hat{i}-2.12\ \hat{j})\ m+(2.71\ \hat{i}+3.59\ \hat{j})\ m\\\Rightarrow \vec{R} = (4.83\ \hat{i}+1.47\ \hat{j})\ m$

Part (a):

We can write the resultant vector R as below:

$\vec{R} = (4.83\ \hat{i}+1.47\ \hat{j})\ m$

Part (b):

$Magnitude\ of\ resultant = \sqrt{4.83^2+1.47^2}\ m = 5.05\ m\\\textrm{Direction in angle with the x-axis} = \theta = \tan^{-1}(\dfrac{1.47}{4.83})= 16.93^\circ$

Since both the components of the resultant lie on the positive x and y axes. So, the resultant makes an acute angle with the positive x-axis.

So, R = (5.05 m, 16.93 degrees wrt x-axis)

3 0

2 years ago

What is the dependent variable in an experiment that shows how the volume of a gas changes with change in temperature?

Natali5045456 [20]

Answer:

Volume of gas

Explanation:

6 0

2 years ago