Note that √2 + √2 = 2√2
2/(2√2) = (√2)/2 = 0.707 (simplified)
0.707 is your answer
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H = 4(x + 3y) + 2
H = 4x + 12y + 2
H - 12y - 2 = 4x
(H - 12y - 2) / 4 = x or 1/4H - 3y - 1/2 = x
Write the vertex form of the equation and find the necessary coefficient to make it work.
.. y = a*(x +3)^2 -2
.. = ax^2 +6ax +9a -2
You require the y-intercept to be 7. So, for x=0, you have
.. 9a -2 = 7
.. 9a = 9
.. a = 1
The equation you seek is
.. y = x^2 +6x +7
Assuming that the figures given are square such that the scale factor between them is equal to 28/8 which can be further simplified into 7/2. The ratio of the perimeter is also equal to this value, 7/2. However, the ratio of the areas is equal to the square of this value giving us an answer of 49/4.
Answer:

Step-by-step explanation:
The volume of the solid revolution is expressed as;

Given y = 2x²
y² = (2x²)²
y² = 4x⁴
Substitute into the formula
![V = \int\limits^2_0 {4\pi x^4} \, dx\\V =4\pi \int\limits^2_0 { x^4} \, dx\\V = 4 \pi [\frac{x^5}{5} ]\\](https://tex.z-dn.net/?f=V%20%3D%20%5Cint%5Climits%5E2_0%20%7B4%5Cpi%20x%5E4%7D%20%5C%2C%20dx%5C%5CV%20%3D4%5Cpi%20%5Cint%5Climits%5E2_0%20%7B%20x%5E4%7D%20%5C%2C%20dx%5C%5CV%20%3D%204%20%5Cpi%20%5B%5Cfrac%7Bx%5E5%7D%7B5%7D%20%5D%5C%5C)
Substituting the limits
![V = 4 \pi ([\frac{2^5}{5}] - [\frac{0^5}{5}])\\V = 4 \pi ([\frac{32}{5}] - 0)\\V = 128 \pi/5 units^3](https://tex.z-dn.net/?f=V%20%3D%204%20%5Cpi%20%28%5B%5Cfrac%7B2%5E5%7D%7B5%7D%5D%20-%20%5B%5Cfrac%7B0%5E5%7D%7B5%7D%5D%29%5C%5CV%20%3D%204%20%5Cpi%20%28%5B%5Cfrac%7B32%7D%7B5%7D%5D%20-%200%29%5C%5CV%20%3D%20128%20%5Cpi%2F5%20units%5E3)
Hence the volume of the solid is 