8^2 + x^2 = 10^2
64 + x^2 = 100
x^2 = 36
x = 6
<h2>
Hello!</h2>
The answer is:
The function is greater or equal to 0 at the points (-3,6), (-2,0), (0,6) and (4,0).
<h2>
Why?</h2>
To find where the function is greater or equal to 0, we need to look (using the graph) where the function is above the x-axis
So, we can see that the function is above the x-axis from the point (-3,6) to the point (4,0), for these points, the function is greater or equal to 0.
Hence, the function is greater or equal to 0 at the points (-3,6), (-2,0), (0,6) and (4,0), or the function is greater or equal to 0, from -3 to 4 (x-axis values or input).
We have that:
![f(-3)=6\\6\geq 0\\\\f(-2)=0\\0=0\\\\f(0)=6\\6\geq 0\\\\f(4)=0\\0=0](https://tex.z-dn.net/?f=f%28-3%29%3D6%5C%5C6%5Cgeq%200%5C%5C%5C%5Cf%28-2%29%3D0%5C%5C0%3D0%5C%5C%5C%5Cf%280%29%3D6%5C%5C6%5Cgeq%200%5C%5C%5C%5Cf%284%29%3D0%5C%5C0%3D0)
Have a nice day!
<span>Let's use the quadratic formula:
2w² -</span><span><span> 20w </span>+ 50 = 0</span>
a = 2 b = -20 c = 50
x = -b +-sq root(b^2 - 4*a*c) / 2*a
x = --20 +-sq root(400 -4*2*50) / 4
x = 20 +-sq root(400 -4*2*50) / 4
x = 20 +-sq root( 0) / 4
x = 20 / 4 =5
I'd say it has one rational solution.
It does NOT have 2 solutions because the "plus / minus" section = 0.
<span>the answer is 2.78 because it add up 10
</span>
Answer:
(4,-4)
Step-by-step explanation:
To find the point which is not a solution, identify the point which is not in the set of solutions. This will be a point which is not in the shaded section of its graph. Graph the inequality by shifting the parent function down 3 units and to the left 4 units. Then flip the graph because of the negative out front. See the attached graph. All the points lie in the shaded except for (4,-4).