Question

Amy has 6 blue, 2 red, and 4 green books to arrange on a shelf. in how many ways can the books be arranged if books of the same color must be grouped together?

Answer 1

3 and 3 on one row blue
2 and 2 on one row green
1 and 1 on one row rd

Answer 2

There are 6! possible permutations of the blue books, 2 possible permutations of the red books, 4! possible permutations of the green books and 3! possible permutations of the three color groups. therefore the total number of ways of arranging the books is given by:
$6!\times2\times4!\times3!=207360\ ways$