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3 years ago

7

When pure hydrazine is placed in an otherwise empty vessel at this temperature equilibrium is reached after 30.0 of the hydrazin

e has decomposed what is the partial pressure of hydrogen gas at equilibrium?

1 answer:

Neko [114]3 years ago

8 0

............................:..

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Geronimo wants to move an object 12 meters. Calculate the net work done by the object with an applied force of 150 N and a frict

valina [46]

Answer:

1476 J

Explanation:

From the question,

Net Work done = Net force× distance moved by net force.

W' = (F-F')×d................... Equation 1

Where W' = Net work done, F = force applied, F' = Frictional force, d = distance moved.

Given: F = 150 N, F' = 37 N, d = 12 m

Substitute these values into equation 1

W' = (150-37)×12

W' = 123×12

W' = 1476 J.

hence the Net Work done by the object is 1476 J

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3 years ago

A high school student ran the 100 meter dash in 12.20 seconds. What was the students. Velocity

sineoko [7]

The student's average speed for the dash was 8.2 m/s. It's not possible to completely describe the student's velocity, because there's no information to tell us what direction she ran.

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4 years ago

Nutritionists call the calories found in junk food _____ calories due to lack of quality nutrients.

Nikolay [14]

Answer:

empty

Explanation:

Nutritionists call the calories found in junk food empty calories due to lack of quality nutrients.

Empty calories refer to calories derived from foods containing no quality nutrients. These foods are mainly junk food; food that contains high calories derived from fat or sugars and with little or no proteins, fiber, dietary minerals or vitamins. These foods are not healthy as their prolonged consumption can lead to an increased risk of obesity.

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4 years ago

Please help me out , im totally stuck on this!?

sladkih [1.3K]

According to first parity rule in a double stranded DNA %A=%T and %G=%C
<span> which means Adenine-Thymine and Guanine-Cytosine these pairs are present in equal amounts
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3 years ago

Noah is loading the ark and the last animal on board is a stubborn 1500-kg elephant who refuses to budge. Noah and his family pu

Oxana [17]

The coefficient of sliding friction is 0.514

Explanation:

We start by writing the equations of motion of the elephant along the two directions, parallel and perpendicular, to the incline.

Along the parallel direction we have:

$F- mg sin \theta - \mu_k R = ma$ (1)

where :

F = 10,000 N is the force applied by Noah

$mg sin \theta$ is the component of the weight parallel to the incline, where:

m is the mass

g = 9.8 m/s^2 the acceleration of gravity

$\theta=10^{\circ}$ is the angle of incline

$\mu_k R$ is the force of friction, where:

$\mu_k$ is the coefficient of friction

R is the normal reaction

and a is the acceleration

Perpendicular direction:

$R-mg cos \theta =0$ (2)

where $mg cos \theta$ is the component of the weight perpendicular to the incline

From (2) we find

$R=mg cos \theta$

And substituting into (1)

$F-mg sin \theta - \mu_k mg cos \theta = ma$

We know that the elephant moves at constant speed, so the acceleration is zero:

a = 0

So the equation becomes

$F-mg sin \theta - \mu_k mg cos \theta=0$

And we can re-arrange it to find the coefficient of friction:

$F-mg sin \theta - \mu_k mg cos \theta=0\\\mu_k = \frac{F-m g sin \theta}{mg cos \theta}=\frac{10000-(1500)(9.8)(sin 10)}{(1500)(9.8)(cos 10)}=0.514$

Learn more about friction and inclined planes:

brainly.com/question/5884009

#LearnwithBrainly

4 0

3 years ago