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IRISSAK [1]
3 years ago
14

A series circuit has four resistors. The current through one resistor is 810 mA. How much current is supplied by the

Physics
1 answer:
Serhud [2]3 years ago
8 0

Answer:

Correct answer:  810 mA

Explanation:

In the series connection of a resistor,the current flowing through one resistor is the same through all four resistors and therefore throughout the entire electrical circuit.

God is with you!!!

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An electron and a proton each have a thermal kinetic energy of 3kBT/2. Calculate the de Broglie wavelength of each particle at a
IgorLugansk [536]

Answer:

The de Broglie wavelength of electron βe = 2.443422 × 10⁻⁹ m

The de Broglie wavelength of proton βp = 5.70 × 10⁻¹¹ m

Explanation:

Thermal kinetic energy of electron or proton = KE

∴ KE = 3kbT/2

given that; kb = 1.38 x 10⁻²³ J/K , T = 1950 K

so we substitute

KE = ( 3 × 1.38 x 10⁻²³ × 1950 ) / 2

kE = 4.0365 × 10⁻²⁰ (  is the kinetic energy for both electron and proton at temperature T )

Now we know that

mass of electron M'e = 9.109 ×  10⁻³¹

mass of proton M'p = 1.6726 ×  10⁻²⁷

We also know that

KE = p₂ / 2m

from the equation, p = √ (2mKE)

{ p is momentum, m is mass }

de Broglie wavelength = β

so β = h / p = h / √ (2mKE)

h = Planck's constant = 6.626 ×  10⁻³⁴

∴ βe =  h / √ (2m'e × KE)

βe = 6.626 ×  10⁻³⁴ / √ (2 × 9.109 ×  10⁻³¹ × 4.0365 × 10⁻²⁰ )

βe = 6.626 ×  10⁻³⁴ / √  7.3536957 × 10⁻⁵⁰

βe = 6.626 × 10⁻³⁴  / 2.71176984642871 × 10⁻²⁵

βe = 2.443422 × 10⁻⁹ m

βp =  h / √ (2m'p ×KE)

βp = 6.626 ×  10⁻³⁴ / √ (2 × 1.6726 ×  10⁻²⁷ × 4.0365 × 10⁻²⁰ )

βp = 6.626 ×  10⁻³⁴ / √ 1.35028998 × 10⁻⁴⁶

βp =  6.626 ×  10⁻³⁴ / 1.16201978468527 ×  10⁻²³

βp = 5.702140 × 10⁻¹¹ m

3 0
3 years ago
What types of areas are more prone to floods?
geniusboy [140]
Areas with poor drainage system
6 0
3 years ago
A single-story retail store wishes to supply all its lighting requirement with batteries charged by photovoltaic cells. The PV c
Umnica [9.8K]

Answer:

83.33% of the roof area will be occupied by the PV cells

Explanation:

Given the data in the question;

time-averaged lighting requirement P_{lighting = 10 W/m²

the annual average solar irradiance q_{solar = 150 W/m²

the PV efficiency η_{pv = 10% = 0.1

battery charging/discharging efficiency η_{battery = 80% = 0.8

we know that; Annual average power to the light = P_{lighting × A_{roof

Now, the electrical power delivered by the solar cell battery system will be;

⇒  q_{solar × A_{pv × η_{pv × η_{battery

P_{lightingA_{roof = q_{solar × A_{pv × η_{pv × η_{battery

Such that;

A_{pv = P_{lightingA_{roof / q_{solar × A_{pv × η_{pv × η_{battery

A_{pv / A_{roof = P_{lighting /  q_{solar × η_{pv × η_{battery

so we substitute

A_{pv / A_{roof = 10 W/m² / [ 150 W/m² × 0.1 × 0.8 ]

A_{pv / A_{roof = 10 W/m² / 12 W/m²

A_{pv / A_{roof = 0.8333

A_{pv / A_{roof = (0.8333 × 100)%

A_{pv / A_{roof = 83.33%

Therefore, 83.33% of the roof area will be occupied by the PV cells.

7 0
3 years ago
A 200-loop coil of cross sectional area 8.5 cm2 lies in the plane of the paper. Directed out of the plane of the paper is a magn
Maslowich

Explanation:

It is given that,

Number of turns, N = 200

Area of cross section, A = 8.5 cm²

Magnetic field is directed out of the paper and is, B = 0.06 T

The magnetic field is  out of the paper decreases to 0.02 T in 12 milliseconds. We need to find the direction of current induced. The induced emf is given by :

\epsilon=-N\dfrac{d\phi}{dt}

Since, \epsilon=IR

I is the induced current

I=-\dfrac{N}{R}\dfrac{d\phi}{dt}

According to Lenz's law, the direction of induced current is such that it always opposes the change in current that causes it.

Here, the field is directed out of the plane of the paper, this gives the induced current in counterclockwise direction.

5 0
3 years ago
A student sets a board to pivot about its center. The student then places a box with mass m at some position r from the pivot po
kvv77 [185]

Answer:

The box should be placed at a distance of \frac{r}{2} from the pivot

Explanation:

In order to be in static equilibrium, both Torques have to be the same magnitude, so:

T_{m} = T_{2m}   Replacing the formula for Torque:

m*r = 2m*X   where X is the distance we need to find.

Solving for X we get:

X = \frac{r}{2}

As we can see, the distance does not depend on the actual value of the mass but on the fact of one being twice as much as the other one.

7 0
4 years ago
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