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Darina [25.2K]
4 years ago
12

Nutritionists call the calories found in junk food _____ calories due to lack of quality nutrients.

Physics
1 answer:
Nikolay [14]4 years ago
6 0

Answer:

empty

Explanation:

Nutritionists call the calories found in junk food empty calories due to lack of quality nutrients.

Empty calories refer to calories derived from foods containing no quality nutrients. These foods are mainly junk food; food that contains high calories derived from fat or sugars and with little or no proteins, fiber, dietary minerals or vitamins. These foods are not healthy as their prolonged consumption can lead to an increased risk of obesity.

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Electromagnetic force is present when electromagnetic fields
AlekseyPX

b is the correct answer

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3 years ago
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A physical proprety of gold is its ?
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Density because it can measured and felt.
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In principle, when you fire a rifle, the recoil should push you backward. How big a push will it give? Let’s find out by doing a
mixer [17]

Answer:

0.07142 m/s in the opposite direction of the bullet

Explanation:

m_1 = Mass of rifle = 70 kg

m_2 = Mass of bullet = 0.01 kg

v_1 = Velocity of rifle

v_2 = Velocity of bullet = 500 m/s

As the momentum of the system is conserved

m_1v_1+m_2v_2=0\\\Rightarrow v_1=-\frac{m_2v_2}{m_1}\\\Rightarrow v_1=-\frac{0.01\times 500}{70}\\\Rightarrow v_1=-0.07142\ m/s

The recoil velocity of the rifle is -0.07142 m/s

The negative sign shows the opposite direction of the rifle.

3 0
3 years ago
A 40 kg bear slides, from rest, 14 m down a lodgepole pine tree, moving with a speed of 3.7 m/s just before hitting the ground.
antiseptic1488 [7]

Answer:

A. -5488J

B. 273.8J

C. 372.44N

Explanation:

Given:

m = 40kg

h = 14 m

v= 3.7 m/s

Part(a)

The change in the potential energy of the bear Earth system during the slide

AU = -mgh = -40(9.8) (14) = -5488 J

Part(b)

The kinetic energy of the bear just before hitting the ground is

Ks 1/2 mV^2= (40)(3.7)2 = 547.6 /2 = 273.8J

Part(c)

The change in the thermal energy of the system due to friction is

AEth = fxh=-(AK +AU) = 5488– 273.8 = 5214.2 J

The average frictional force that acts on the sliding bear is

F = Eth / 14= 5214.2/14 =372.44N

4 0
3 years ago
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