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Rus_ich [418]
3 years ago
8

How can you turn .375 into a percent

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
8 0
The answer is 37.5 thank you
Lyrx [107]3 years ago
5 0
To convert a decimal to percentage, we multiply the number by 100.

0.375 = 0.375 x 100% = 37.5%

Answer: 37.5%
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Find the number of subsets of the set {1, 2, 3, ..., 9}
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512

Step-by-step explanation:

the number of subsets of the set {1, 2, 3, ..., 9} is : 2^9 = 512

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What is the surface area
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<span>The outside part or uppermost layer of something (often used when describing its texture, form, or extent).</span>
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Which of these equations are true when the value of y is 27?
Troyanec [42]

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Step-by-step explanation:

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3 years ago
A local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle. In o
Mandarinka [93]

Answer:

(a) Null Hypothesis, H_0 : \mu = 22 ounces  

    Alternate Hypothesis, H_A : \mu\neq 22 ounces

(b) The value of the test statistic is -2.687.

(c) The critical values are -1.96 and 1.96.

(d) We conclude that Reject H_0 since the value of the test statistic is less than the negative critical value.

Step-by-step explanation:

We are given that a local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle.

He takes a random sample of 65 bottles. The mean weight of the passion fruit juice in the sample is 21.54 ounces. Assume that the population standard deviation is 1.38 ounce.

<em>Let </em>\mu<em> = average ounces of passion fruit juice used to fill each bottle.</em>

(a) So, Null Hypothesis, H_0 : \mu = 22 ounces     {means that the average of 22 ounces of passion fruit juice is used to fill each bottle}

Alternate Hypothesis, H_A : \mu\neq 22 ounces     {means that the average different from 22 ounces of passion fruit juice is used to fill each bottle}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                        T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean weight of the passion fruit juice = 21.54 ounces

            \sigma = population standard deviation = 1.38 ounce

            n = sample of bottles = 65

So, <u><em>test statistics</em></u>  =  \frac{21.54-22}{\frac{1.38}{\sqrt{65} } }  

                               =  -2.687

(b) The value of z test statistics is -2.687.

(c) Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

<em>Since our test statistics does not lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><u><em>we reject our null hypothesis</em></u><em>.</em>

Therefore, we conclude that Reject H_0 since the value of the test statistic is less than the negative critical value which means that the average different from 22 ounces of passion fruit juice is used to fill each bottle.

6 0
3 years ago
HECTOR PLANTED 185 FLOWERS IN 2 DAYS THERE WERE 5 VOLUNTEERS INCLUDING HECTOR WHO EACH PLANTED ABOUT THE SAME NUMBER OF FLOWERS
Svet_ta [14]
The answer is very simple each had planted 37 flowers

3 0
3 years ago
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