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2 years ago

How do I find the x-Interception of -2(8+3)^2 +8

Mathematics

1 answer:

nevsk [136]2 years ago

8 0

Answer: There is no x intercept.

Step-by-step explanation:

That is not a function.

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Graph each equation<br> Y=-2|-3X+3|+4<br><br> NEED HELP ASAP!!

HACTEHA [7]

Graph the absolute value by using the vertex and a few selected points

Point One: X= -1, Y= -8

Point Two: X= 0, Y= -2

Point Three: X= 1, Y= 4

Point Four: X= 2, Y= -2

Point Five: X= 3, Y= -8

The graph should look something like a mountain or an upside down V

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3 years ago

-2(x+2=x-3(x+1)-1 please help me

Tcecarenko [31]

The solution would be x=0 because the statement is false.

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2 years ago

Ryan made $119 for 7 hours of work.

Korvikt [17]

Answer:

128

Step-by-step explanation:

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2 years ago

Read 2 more answers

$89.75 scooter; 7 1/4% tax

Kazeer [188]

If you are looking for the sales tax then you take 89.75 times .075 this will give you 6.73 now you just add 6.73 to 89.75 and you get..

sales tax = $96.48

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2 years ago

Find the radius of the circle with equation x²+y²+8x+8y+28=0

galina1969 [7]

<h2>Hello!</h2>

The answer is:

Center: (-4,-4)

Radius: 2 units.

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

$(x-h)^{2}+(y-k)^{2}=r^{2}$

Where:

"h" and "k" are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

$x^{2}+y^{2}+8x+8y+28=0$

So, solving we have:

$x^{2}+y^{2}+8x+8y=-28$

$(x^2+8x+(\frac{8}{2})^{2})+(y^2+8y+(\frac{8}{2})^{2})=-28+((\frac{8}{2})^{2})++(\frac{8}{2})^{2})\\\\(x^2+8x+16 )+(y^2+8y+16)=-28+16+16\\\\(x^2+4)+(y^2+4)=4$

$(x^2-(-4))+(y^2-(-4))=4$

Now, we have that:

$h=-4\\k=-4\\r=\sqrt{4}=2$

So,

Center: (-4,-4)

Radius: 2 units.

Have a nice day!

Note: I have attached a picture for better understanding.

3 0

2 years ago