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kogti [31]
3 years ago
13

I need help with 3, 5, 8, and 10

Mathematics
1 answer:
777dan777 [17]3 years ago
6 0
Hope this can help you

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Which expression is equivalent to 1/8x- 1/2?
pychu [463]
This is done by factoring.  1/8 is smaller than 1/2, so we can factor a 1/8 out of 1/2.  This is what that looks like: \frac{ \frac{1}{2} }{ \frac{1}{8} }, because factoring after all is a form of division.  When we divide a fraction by a fraction, we bring the lower fraction up and flip it to multiply, giving us this: \frac{1}{2} * \frac{8}{1}.  This of course reduces to 4.  So when we factor out 1/8, what we will have then is \frac{1}{8} (x-4), choice D from above.
6 0
3 years ago
Which of these strategies would eliminate a variable in the system of equations?
natali 33 [55]

Answer:Multiply the top equation by -3 , then add the questions .

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Factor the difference of cubes. Select prime if the polynomial cannot be factored
tester [92]

Answer:

(m-(1/3))(m^2+(1/3)m+(1/9)

Step-by-step explanation:

Just use the difference of cubes

3 0
3 years ago
N is a positive integer
Murrr4er [49]

Part (1)

n is some positive integer. Let's say for now that n is even. So n = 2k, for some integer k

This means n-1 = 2k-1 is odd since subtracting 1 from an even number leads to an odd number.

Now multiply n with n-1 to get

n(n-1) = 2k(2k-1) = 2m

where m = k(2k-1) is an integer

The result 2m is even showing that n(n-1) is even

------------

Let's say that n is odd this time. That means n = 2k+1 for some integer k

And also n-1 = 2k+1-1 = 2k showing n-1 is even

Now multiply n and n-1

n(n-1) = (2k+1)(2k) = 2k(2k+1) = 2m

where m = k(2k+1) is an integer

We've shown that n(n-1) is even here as well.

------------

So overall, n(n-1) is even regardless if n is even or if n is odd.

Either n or n-1 will be even. If you multiply an even number with any number, the result will be even.

=======================================================

Part (2)

n is some positive integer

2n is always even since 2 is a factor of 2n

2n+1 is always odd because we're adding 1 to an even number. The sequence of integers goes even,odd,even,odd, etc and it does this forever.

-----------

Another way to see how 2n+1 is odd is to divide 2n+1 over 2 and you'll find that we get (2n+1)/2 = 2n/2+1/2 = n+0.5

The 0.5 at the end is not an integer, so there's no way that (2n+1)/2 is an integer; therefore 2n+1 is odd.

6 0
3 years ago
What is the value of x?<br> a. 2 /29<br> b. 3 /61<br> c. 2/ 101<br> d. 2/333
stiv31 [10]

Answer:

2√133

Step-by-step explanation:

a²+b²=c²

8²+12²=c²

c²=208

208+18²=532

√532=23

3 0
3 years ago
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