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xxMikexx [17]
3 years ago
10

Write the recurring decimal 0 32 . o as a fraction. You must show all your working

Mathematics
1 answer:
Mrrafil [7]3 years ago
6 0

Answer:

the answer is 8/25

Step-by-step explanation:

arrange in rational number 32/100 since both can be divided by 4 therefore 8/25

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-8(2r - 8)+ 6 = -3(r + 7)
nordsb [41]

Answer:

r = 7

Step-by-step explanation:

Use the distributive property by multipling the -8 to the 2r and the -8, do the same thing on the other side with the -3.

Afterwards, combine like terms by adding 64 and 6.

Next, add 3r to the left side, I usually choose the number with the variable (the letter) that looks like it will be easier to subtract. This leaves only 21 on the right side.

Next subtract 70 from both sides

Divide -13 by both sides

You should get the answer of r=7

4 0
3 years ago
Which matrix represents the solution to this system of equations?
Xelga [282]

Answer:

1. b

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect
Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99

Compute the probability that a person does not have the disease as follows:

P(D^{c})=1-P(D)=1-0.88=0.12

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188

Compute the probability that a randomly selected person is tested negative  as follows:

P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})

           =0.0264+0.1188\\=0.1452

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0
3 years ago
The linear functions f(x) and g(x) are represented on the graph, where g(x) is a transformation of f(x):
Brilliant_brown [7]

Answer:

Part A: Determine the test average for your math class after completing test 2. (2 points)

Part B: Determine the test average for your science class after the completing test 2. (2 points)

Part C: Which class had a higher average after completing test 4? Show work to support your answer. (6 points)

I am finding itz answer, pls help

7 0
2 years ago
A retail company estimates that if it spends x thousands of dollars on advertising during the year, it will realize a profit of
Gwar [14]

Answer:

Step-by-step explanation:

If the profit realized by the company is modelled by the equation

P (x) = −0.5x² + 120x + 2000, marginal profit occurs at dP/dx = 0

dP/dx = -x+120

P'(x) = -x+120

Company's marginal profit at the $100,000 advertising level will be expressed as;

P '(100) = -100+120

P'(100) = 20

Marginal profit at the $100,000 advertising level is $20,000

Company's marginal profit at the $140,000 advertising level will be expressed as;

P '(140) = -140+120

P'(140) = -20

Marginal profit at the $140,000 advertising level is $-20,000

<u>Based on the marginal profit at both advertising level, I will recommend the advertising expenditure when profit between $0 and $119 is made. At any marginal profit from $120 and above, it is not advisable for the company to advertise because they will fall into a negative marginal profit which is invariably a loss.</u>

7 0
3 years ago
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