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dlinn [17]
3 years ago
5

A taxi charges a flat rate of $1.75, plus an additional $0.65 per mile. If Erica has at most $10 to spend on the cab ride, how f

ar could she travel?
Mathematics
1 answer:
yaroslaw [1]3 years ago
3 0

Answer: 12.69 miles approx

Step-by-step explanation:

let x represent the number of miles traveled

1.75 + 0.65x = 10

0.65x  = 8.25

x = 12.69 miles approx

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Karli's shadow is 60 inches long. A nearby fire hydrant casts a shadow 40 inches long. If Karli is 48 inches tall, what is the h
Mademuasel [1]
The answer is twenty eight
8 0
4 years ago
Please help me! DO NOT SEND LINK!
svet-max [94.6K]

Answer:

<u>So option 4; </u>\frac{35}{100}<u> is the correct option</u>

Step-by-step explanation:

First, we need to convert \frac{2}{10} so it's denominator is 100. To do so, we will multiply the numerator and denominator by 10

\frac{2}{10} *\frac{10}{10} = \frac{20}{100}

Second, we need to add the two fractions to get the current total distance walked. Remember, when adding fractions, the denominator does not change.

\frac{45}{100} + \frac{20}{100} = \frac{65}{100}

Now that we have the total distance walked, we need to subtract that to 1 mile. 1mile=\frac{1}{1} = \frac{10}{10} =\frac{100}{100}

\frac{100}{100} -\frac{65}{100} = \frac{35}{100}

So option 4; \frac{35}{100} is the correct option

6 0
3 years ago
Please help right in <br>y=mx+b form
slavikrds [6]
Y=2/2x+0
hope this helps

ps~~u dont need that 0
4 0
4 years ago
16 POINTS. Find x and y intercepts and show work. <br><br> I’m looking for number six.
aliya0001 [1]
X^4-3x³+4x
x^4-3x³+3x+x
(x^4+x)-(3x³-3x)
x(x³+1)-3x(x²-1)
x(x+1)(x²-x+1)-3x(x+1)(x-1)
x(x+1)(x²-x+1-3x+3)
x(x+1)(x²-4x+4)
x(x+1)(x-2)(x-2)
so x intercepts are (0,0), (-1,0) and (2,0)
the y intercept is (0,0)

8 0
3 years ago
More help is appreciated:))
Lera25 [3.4K]

Step-by-step explanation:

You need to translate all the points to the right 3 and up 6

Therefore, you are going to use this formula:

(x,y) ⇾ (x + 3, y + 6)

This is the same format as the previous problem, if you have noticed.

Using this, plug in each coordinate, starting with  P (5, -1)

(5, -1) ⇾ ( 5 + 3, -1 + 6)

(5, -1) ⇾ ( 8, 5 )

P^{1} = (8, 5)

Now point Q, (0, 8)

(0, 8) ⇾ (0 + 3, 8 + 6)

(0, 8) ⇾ ( 3, 14 )

Q^{1} = (3, 14)

And last but not least, the point R, (7, 5)

(7, 5) ⇾ (7 + 3, 5 + 6)

(7, 5) ⇾ ( 10, 11 )

R^{1} = (10, 11)

Therefore, P^{1} = (8, 5), Q^{1} = (3, 14), R^{1} = (10, 11) is your answer. This is the 4th option or D.

Hope this for you to understand this a bit more! =D

6 0
3 years ago
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