Face value of a note payable plus interest is called
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Where the variance is 0.32, the mean is 0.40, and there are provided sets of probabilities, the standard deviation will be 0.566.
<h3>What is standard deviation?</h3>The average degree of variability in your dataset is represented by the standard deviation. It reveals the average deviation of each statistic from the mean. In general, values with a high standard deviation are spread out from the mean, whereas those with a low standard deviation are grouped together close to the mean.
Here,
mean=0.4
variance=(Xn-mean)².P(x)n
=(0-0.4)²*(0.64)+(1-0.4)²*(0.32)+(2-0.4)²*0.04
variance=0.32
Standard deviation=√(variance)
=√0.32
=0.566
The standard deviation will be 0.566 where variance in 0.32 and mean is 0.40 and given sets of probability.
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Answer:
DNE
Step-by-step explanation:
The the given table, we have;
As x approaches -14 from the left, at x = -14.001, p(x) = 1.96
As x approaches -14 from the right, at x = -13.999, p(x) = 1.97
The value of p(x) when x = -14 is = Undefined, or is not definable, therefore, p(x) Does Not Exist (DNE) when x = -14, and we have;
Does Not Exist, DNE.