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DochEvi [55]
3 years ago
10

What is 5/6 divided by 2/7

Mathematics
2 answers:
kati45 [8]3 years ago
5 0
5/6 divided by 2/7
Convert the divided sign into a multiplication sign while transforming 2/7 to 7/2
5/6 * 7/2
Multiply the numerator by the other numerator while multiplying the denominator by the other denominator.
Final Answer: 35/12 or 2 11/12
Iteru [2.4K]3 years ago
3 0
5/6 / 2/7 becomes 5/6 * 7/2 = 35/12 = 2 11/12.
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6 more than 5 times a number y
natta225 [31]
6+5y is the equation
7 0
3 years ago
Read 2 more answers
Find the slope C(-8,-7) and D (13,-1
DaniilM [7]

So you will use slope formula which is m = (y2 -- y1) / (x2 -- x1)

-1 minus -7=6

13 minus -8=21

Remember it changes to a positive Keep,Change,Change

So its 6/21

Or 1/4

Ask questions if you still need help

:)


3 0
3 years ago
A sample size 25 is picked up at random from a population which is normally
Margarita [4]

Answer:

a) P(X < 99) = 0.2033.

b) P(98 < X < 100) = 0.4525

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 100 and variance of 36.

This means that \mu = 100, \sigma = \sqrt{36} = 6

Sample of 25:

This means that n = 25, s = \frac{6}{\sqrt{25}} = 1.2

(a) P(X<99)

This is the pvalue of Z when X = 99. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{99 - 100}{1.2}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033. So

P(X < 99) = 0.2033.

b) P(98 < X < 100)

This is the pvalue of Z when X = 100 subtracted by the pvalue of Z when X = 98. So

X = 100

Z = \frac{X - \mu}{s}

Z = \frac{100 - 100}{1.2}

Z = 0

Z = 0 has a pvalue of 0.5

X = 98

Z = \frac{X - \mu}{s}

Z = \frac{98 - 100}{1.2}

Z = -1.67

Z = -1.67 has a pvalue of 0.0475

0.5 - 0.0475 = 0.4525

So

P(98 < X < 100) = 0.4525

6 0
3 years ago
Which best describes a transformation that preserves the size, shape, and angles of an object? A. congruent transformation B. no
Harrizon [31]

Answer:

Your answer would be D: isometry

Step-by-step explanation:


6 0
3 years ago
4. A sequence of transformations was applied to an equilateral triangle in a coordinate plane.
forsale [732]

Step-by-step explanation:

A It must be an equilateral triangle with the same side lengths as the original triangle

8 0
3 years ago
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