Answer:
1. (x + 2)² + (y - 9)² = 64
2. (x + 6)² + (y - 9/2)² = 100
3. (x - 15)² + (y + 10)² = 1
Step-by-step explanation:
Equation of a circle:
(x - h)² + (y - k)² = r²
1. Center: (-2, 9), Radius: 8
(x - (-2))² + (y - 9)² = 8²
(x + 2)² + (y - 9)² = 64
2. Center: (-6, 9/2), Radius: 10
(x - (-6))² + (y - (9/2))² = 10²
(x + 6)² + (y - 9/2)² = 100
3. Center: (15, -10), Radius: 1
(x - 15)² + (y - (-10))² = 1²
(x - 15)² + (y + 10)² = 1
Answer:
blue
Step-by-step explanation:
Its blue because if purple has 2 and blue has 1 then its blue which you are most likely to pick purple then blue
Answer:
Step-by-step explanation
Let's say d = distance, r = speed and t = time
We know the distance formula is :
distance = speed x time
d = r multiplied by t
d = rt
If the speed is 15km/hr, the time would be 30 minutes shorter.
Since d = rt,
90 = 15t
t = 6,
This means the time taken for the bus to complete the journey at 15km/hr would be 6hrs.
Originally though, the journey takes 30 minutes longer.
So we can say t = 6.5 hrs , and we know d = 90
Now we use the distance formula:
d = rt, since we want to find the original speed, we want to find r.
Speed = distance/time
r = d/t
r = 90/6.5
r = 180/13
Therefore the original speed is 180/13 km/hr
Answer:
0.7
Step-by-step explanation:
0.7x10=7
Answer:
The correct options are:
Option B)
is never zero.
Option F) When x=0, y≠0
Step-by-step explanation:
Consider the provided function.
![y=4^x](https://tex.z-dn.net/?f=y%3D4%5Ex)
When we substitute x=0 in above function we get:
![y=4^{0}](https://tex.z-dn.net/?f=y%3D4%5E%7B0%7D)
![y=1](https://tex.z-dn.net/?f=y%3D1)
When we substitute x=-1 in above function we get:
![y=4^{-1}](https://tex.z-dn.net/?f=y%3D4%5E%7B-1%7D)
![y=0.25](https://tex.z-dn.net/?f=y%3D0.25)
When we substitute x=1 in above function we get:
![y=4^{1}](https://tex.z-dn.net/?f=y%3D4%5E%7B1%7D)
![y=4](https://tex.z-dn.net/?f=y%3D4)
The above function is exponential function which does not pass through the origin and the range of the function is a positive number.
The graph of the function is shown in figure 1.
Now consider the provided options.
Option A)
is always greater than or equal to 1.
The option is incorrect as the value of the function is less than 1 for negative value of x.
Option B)
is never zero
The option is correct.
Option C) When y=0, x=0
The option is incorrect.
Option D) When x=0, y=4
When x=0 the value of y is 1.
Thus, the option is incorrect.
Option E)
is zero when x=0
When x=0 the value of
is 1.
Thus, the option is incorrect.
Option F) When x=0, y≠0
The option is correct as 0≠1.