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3 years ago

Sin167cos107-cos167sin107

1 answer:

6 0

Sin 167 = 0.22495

cos 107 = -0.29237

cos 167 = -0.97437

sin 107 = 0.95630

(sin 167)(cos 107) - (cos 167)(sin 107)

(0.22495)(-0.29237) - ( -0.97437)(0.95630)

= 0.86602

hope this helps :)

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(Subtract<br> ) f(x) = x + 1<br> g(x) = x2 + 1

kramer

Answer:

The first question:

x = -1

Step-by-step explanation:

Step 1 :

Pulling out like terms :

1.1 Pull out like factors :

-x - 1 = -1 • (x + 1)

Equation at the end of step 1 :

Step 2 :

Solving a Single Variable Equation :

2.1 Solve : -x-1 = 0

Add 1 to both sides of the equation :

-x = 1

Multiply both sides of the equation by (-1) : x = -1

One solution was found :

x = -1

Processing ends successfully

plz mark me as brainliest :)

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3 years ago

A circle has the order pairs (-1, 2) (0, 1) (-2, -1) what is the equation . Show your work.

olga55 [171]

We know that:

$(x-a)^2+(y-b)^2=r^2$

is an equation of a circle.

When we substitute x and y (from the pairs we have), we'll get a system of equations:

$\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}$

and all we have to do is solve it for a, b and r.

There will be:

$\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}\\\\\\
\begin{cases}1+2a+a^2+4-4b+b^2=r^2\\a^2+1-2b+b^2=r^2\\4+4a+a^2+1+2b+b^2=r^2\end{cases}\\\\\\
\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\\\\\
$

From equations (II) and (III) we have:

$\begin{cases}a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\--------------(-)\\\\a^2+b^2-2b+1-a^2-b^2-4a-2b-5=r^2-r^2\\\\-4a-4b-4=0\qquad|:(-4)\\\\\boxed{-a-b-1=0}$

and from (I) and (II):

$\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\end{cases}\\--------------(-)\\\\a^2+b^2+2a-4b+5-a^2-b^2+2b-1=r^2-r^2\\\\2a-2b+4=0\qquad|:2\\\\\boxed{a-b+2=0}$

Now we can easly calculate a and b:

$\begin{cases}-a-b-1=0\\a-b+2=0\end{cases}\\--------(+)\\\\-a-b-1+a-b+2=0+0\\\\-2b+1=0\\\\-2b=-1\qquad|:(-2)\\\\\boxed{b=\frac{1}{2}}\\\\\\\\a-b+2=0\\\\\\a-\dfrac{1}{2}+2=0\\\\\\a+\dfrac{3}{2}=0\\\\\\\boxed{a=-\frac{3}{2}}$

Finally we calculate $r^2$ :

$a^2+b^2-2b+1=r^2\\\\\\\left(-\dfrac{3}{2}\right)^2+\left(\dfrac{1}{2}\right)^2-2\cdot\dfrac{1}{2}+1=r^2\\\\\\\dfrac{9}{4}+\dfrac{1}{4}-1+1=r^2\\\\\\\dfrac{10}{4}=r^2\\\\\\\boxed{r^2=\frac{5}{2}}$

And the equation of the circle is:

$(x-a)^2+(y-b)^2=r^2\\\\\\\left(x-\left(-\dfrac{3}{2}\right)\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}\\\\\\\boxed{\left(x+\dfrac{3}{2}\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}}$

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3 years ago

What is the average rate of change of the function f(x) = 5x ^ 2 + 20x between x = 0 and x = 0.5

Vitek1552 [10]

9514 1404 393

Answer:

22.5

Step-by-step explanation:

The average rate of change on the interval [a, b] is the ratio ...

(f(b) -f(x))/(b -a)

For your function and interval, it is ...

(f(0.5) -f(0))/(0.5 -0)

Since f(0) = 0, this reduces to ...

average rate of change = 2·f(0.5) = 2(5(0.5)² +20(0.5)) = 2(5/4 +10)

average rate of change = 22.5

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3 years ago

We know that Martin is buying some apples at $0.75 each and two dozen oranges

Daniel [21]

Step-by-step explanation:

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is the correct answer

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2 years ago

What is the multiplicative rate of change of the function?

AleksandrR [38]

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Step-by-step explanation:

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3 years ago