You always begin by the Given equation, which is in this case: y+ = 3x To remove the fraction, you multiply the whole equation by 5: 5y + 1 = 15x Then, you move the "15x" the left-side of the equation, changing it's sign -15x + 5y +1 = 0 You move the "1" to the right side, changing it's sign -15x + 5y = -1 So the correct answer is A :) Hope it helped! ^^
Standard form is ax+by=c where a and b are integers and a is normally positive
y+1/5=3x minus 3x both sides -3x+y+1/5= mnus 1/5 both sides -3x+y=-1/5 times both sides by -5 15x-5y=1 seems they want x to be negative multiply by -1 -15x+5y=-1