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Tamiku [17]
3 years ago
14

which equation shows y+1/5=3x in standard form? A. -15x+5y=-1 B. -5x+15y=-1 C. -15x+5y=1 D. 15x+5y=-1

Mathematics
2 answers:
dmitriy555 [2]3 years ago
5 0
You always begin by the Given equation, which is in this case:
y+\frac{1}{5} = 3x
To remove the fraction, you multiply the whole equation by 5:
5y + 1 = 15x
Then, you move the "15x" the left-side of the equation, changing it's sign
-15x + 5y +1 = 0
You move the "1" to the right side, changing it's sign
-15x + 5y = -1
So the correct answer is A :)
Hope it helped! ^^
iren [92.7K]3 years ago
5 0
Standard form is ax+by=c where a and b are integers and a is normally positive

y+1/5=3x
minus 3x both sides
-3x+y+1/5=
mnus 1/5 both sides
-3x+y=-1/5
times both sides by -5
15x-5y=1
seems they want x to be negative
multiply by -1
-15x+5y=-1

A
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