3 years ago

which equation shows y+1/5=3x in standard form? A. -15x+5y=-1 B. -5x+15y=-1 C. -15x+5y=1 D. 15x+5y=-1

2 answers:

5 0

You always begin by the Given equation, which is in this case:
y+ $\frac{1}{5}$ = 3x
To remove the fraction, you multiply the whole equation by 5:
5y + 1 = 15x
Then, you move the "15x" the left-side of the equation, changing it's sign
-15x + 5y +1 = 0
You move the "1" to the right side, changing it's sign
-15x + 5y = -1
So the correct answer is A :)
Hope it helped! ^^

iren [92.7K]3 years ago

5 0

Standard form is ax+by=c where a and b are integers and a is normally positive

y+1/5=3x
minus 3x both sides
-3x+y+1/5=
mnus 1/5 both sides
-3x+y=-1/5
times both sides by -5
15x-5y=1
seems they want x to be negative
multiply by -1
-15x+5y=-1

A

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What is the cube root of -729a^9b^6? -9a^3b^2 -9a^2b^ -8a^3b^2 -8a^2b^3

timurjin [86]

Answer:

$= 9a^3b^2$

Step-by-step explanation:

$\sqrt[3]{-729a^9b^6} =$

$= ((-9)^3a^9b^6)^{\frac{1}{3}$

$= (-9)^{3 \times \frac{1}{3}} \times a^{9 \times \frac{1}{3}} \times b^{6 \times \frac{1}{3}}$

$= (-9)^{1} \times a^{3} \times b^{2}$

$= -9a^3b^2$

7 0

2 years ago

Can someone help me with this please!~

Eduardwww [97]

Note that sum of triangle interior angles is 180. So,

$(12x+12)+15+(3x+18)=180$

$15x+45=180$

$15x=135$

$x=9$

Since $A=12x+12=12.9+12=120$

And $C=3x+18=3.9+18=45$