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Alexandra [31]
3 years ago
9

5. Create a vector called to20 that goes from 1 to 20 (use the range notation). Now create a variable called end that goes from

40 to 50 (use the range notation). Now create a variable called to50 that combines to20, then the number 21 to 30 and then add thes end variable at the end. Now print the variable to50. It should output the numbers 1 through 30 and then 40 through 50, skipping 31-39.
Computers and Technology
1 answer:
Lady_Fox [76]3 years ago
8 0

Answer:

creating vector:

code:  

to20 <-c(1:20) #creating to20 vector

end <-c(40:50) #creating end vector

to50 <-c(to20,21:30,end) # creating to50 vector

print(to50) # printing to50 vector

Explanation:

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Answer:

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Сквозь грозы сияло нам солнце свободы,

И Ленин великий нам путь озарил.

Нас вырастил Сталин - на верность народу

На труд и на подвиги нас вдохновил.

Славься, Отечество чаше свободное,

Счастья народов надежный оплот!

Знамя советское, знамя народное

Пусть от победы к победе ведет!

Skvoz grozy siialo nam solntse svobody,

I Lenin velikij nam put ozaril.

Nas vyrastil Stalin - na vernost narodu

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Пусть от победы к победе ведет!Explanation:

8 0
3 years ago
List five ways in which the type declaration system of a language such as Java or C differs from the data definition language us
zhannawk [14.2K]

Answer:

Hi Sevanah! Below are the five main differences between a type declarative language and a data definition language:

A data definition language:

1. define data structure

2. define the column attributes of a table

3. no further classifications

4. The basic commands in a Data Definition language are CREATE, DROP, RENAME, ALTER

5. Scope of variables in data definition languages is limited  

A type declarative language:

1. manipulate the data itself

2. uses functions to add and update the rows of a table

3. further classified into procedural and non-procedural languages

4. The basic commands are INSERT, UPDATE and MERGE

5. Scope of variables in type declarative languages is varied

Explanation:

A data definition language is used to define data structures. It makes use of statements such as create table, alter table to create and alter the database schema to allow it to hold rows of information. A type declarative language such as Java or C is used to manipulate the data itself. For example, insert, update and deletion of rows to the database. Whereas data definition languages define the column attributes of a table, a type declaration language uses functions to add and update the rows of a table. A data definition language does not have any further classification, however a type declarative language can be further classified into procedural and non-procedural languages. The basic commands in a Data Definition language are CREATE, DROP, RENAME, ALTER, whereas the basic commands in a type declarative language are INSERT, UPDATE and MERGE. There is little of no scope of variables in a data definition language, whereas the scope of variables in type declarative languages is varied

8 0
3 years ago
The collection of computer instructions and other files that constitute a piece of software is
lutik1710 [3]
The answer would be
A. Codebase

8 0
3 years ago
Read 2 more answers
Write a program that prompts the user to enter in a postive number. Only accept positive numbers - if the user supplies a negati
marusya05 [52]

Answer:

The c++ program to check prime numbers is shown below.

#include <iostream>

using namespace std;

int main() {

   int num, prime=0;

   do

   {

       cout<<"Enter a positive number."<<endl;

       cin>>num;

       if(num<1)

       {

           cout<<"Invalid number. Enter a positive number"<<endl;

           cin>>num;

       }

   }while(num<1);

   

   if(num==1 || num==2 || num==3)

       cout<<num<<" is a prime number."<<endl;

   else if(num%2 == 0)

       cout<<num<<" is not a prime number."<<endl;

   else

   {

       for(int k=3; k<num/2; k++)

       {

           if(num%k == 0)

               prime++;

       }    

   if(prime>1)

       cout<<num<<" is not a prime number."<<endl;

   else

       cout<<num<<" is a prime number."<<endl;

   }

}

OUTPUT

Enter a positive number.

-7

Invalid number. Enter a positive number

0

Enter a positive number.

79

79 is a prime number.

Explanation:

The user input is validated for positivity. A do while loop along with an if statement is implemented for verification.

do

   {

       cout<<"Enter a positive number."<<endl;

       cin>>num;

       if(num<1)

       {

           cout<<"Invalid number. Enter a positive number"<<endl;

           cin>>num;

       }

   }while(num<1);

The test for prime number is done by using multiple if else statements.

If user inputs 1, 2, or 3, message is displayed.

Else If user inputs an even number, message is displayed for not prime. This is done by taking modulo of the number upon division by 2.

Else if user inputs neither an even number nor a number less than 3, the modulus of the number is taken with divisors beginning from 3 up to half of the input number.

For this, an integer variable prime is initialized to 0. A number can be completely divisible by itself or by its factors.

If the number is divisible by any of the divisors, value of variable prime is increased by 1. If value of prime is greater than 1, this means that the user input is divisible by more than one divisor. Hence, the given number is not a prime number.

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3 years ago
In a game with three frames, where will the objects on Layer 1 appear?
Ivan
It’s between d or c
6 0
3 years ago
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