Answer:
The correct answer is letter "A": commit with fallback.
Explanation:
American Professor Alfred A. Marcus (born 1950) in his book "<em>The Future of Technology Management and the Business</em>" (2015) describes that hedging may be a strategy to shield businesses from the rapidly evolving world they face as a result of the continuous implementation of technology in the market. According to Marcus, there are 5 hedge approaches that firms should implement:
- Gamble on the most probable:<em> work on the product with the highest success rate.
</em>
- Take the robust route: <em>invest in as many products as possible.
</em>
- Delay until further clarity emerges:<em> waiting for a proper moment to react in front of market changes.
</em>
- <u>Commit with a fallback</u>:<em> adapt according to the market.
</em>
- Try to shape the future:<em> innovate.</em>
Answer:
import java.util.Scanner;
public class Main
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter a number: ");
int userVal = input.nextInt();
String aString;
if(userVal < 0)
aString = "negative";
else
aString = "non-negative";
System.out.println(aString);
}
}
Explanation:
Ask the user to enter a number and set it to userVal
Check the value of userVal. If it is smaller than 0, set the string as "negative". If it is not, set it as "non-negative"
Print the string
Answer:
Explanation:
The following code is written in Python. It creates a method for each one of the questions asked and then tests all three with the same test case which can be seen in the picture attached below.
def alternating_list(lst1, lst2):
lst3 = []
for x in range(len(lst1)):
lst3.append(lst1[x])
try:
lst3.append(lst2[x])
except:
pass
if len(lst2) > len(lst1):
lst3.extend(lst2[len(lst1):])
return lst3
def reverse_alternating(lst1, lst2):
lst3 = []
if len(lst1) == len(lst2):
for x in range(len(lst1) - 1, -1, -1):
lst3.append(lst1[x])
lst3.append(lst2[x])
return lst3
def alternating_list_no_extra(lst1, lst2):
lst3 = []
max = 0
if len(lst1) > len(lst2):
max = len(lst2)
else:
max = len(lst1)
for x in range(max):
lst3.append(lst1[x])
try:
lst3.append(lst2[x])
except:
pass
return lst3
Answer:
Metrical task system algorithm is the online algorithm that is used for organizing the online problems like k-server issues, paging issues etc.This task system works in the form of metrics to decrease the complete cost experienced due to processing of the operation and analyzing the competition.
It can be used for the online shopping project for the analyzing the comparison between the performance on basis of online and offline trends and then optimization can take place according to the the results.
Answer:
<em>Solution</em>:
The statements are listed below.
<em>(A) Functional requirement </em>
- Functional specifications refer to the handling of calls.
- Minimum call number should be 3000, and a functional requirement.
<em>(B) Non-functional requirement</em>
- Non-functional requirement is the default option.
- Payment in "Visa" is required and this is not a functional requirement.
<em>(C) Data requirements</em>
- Data requirements apply to quantity of order.
- When the quantity of data exceeds then an exception should be notified
<em>(D) Business requirements. </em>
- Product reviews are subject to business requirements.
