7 is a factor of 14 and is not a multiple of 2.
Answer:
x^2(squared) +2x+1
Step-by-step explanation:
Answer: 2343
Step-by-step explanation:
Answer:
a) It can be used because np and n(1-p) are both greater than 5.
Step-by-step explanation:
Binomial distribution and approximation to the normal:
The binomial distribution has two parameters:
n, which is the number of trials.
p, which is the probability of a success on a single trial.
If np and n(1-p) are both greater than 5, the normal approximation to the binomial can appropriately be used.
In this question:

So, lets verify the conditions:
np = 201*0.45 = 90.45 > 5
n(1-p) = 201*(1-0.45) = 201*0.55 = 110.55 > 5
Since both np and n(1-p) are greater than 5, the approximation can be used.
Answer:
hello your question is incomplete attached below is the complete question
answer :
for I1 =
The integral converges
for I2 =
The integral diverges
for I3 =
The integral converges
for I4 = 1 The integral diverges
Step-by-step explanation:
The similar integrands and the prediction ( conclusion )
for I1 =
The integral converges
for I2 =
The integral diverges
for I3 =
The integral converges
for I4 = 1 The integral diverges
attached below is a detailed solution