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irga5000 [103]
3 years ago
7

Solve the system of equations. -10y+9x=-9 10y+5x=-5

Mathematics
1 answer:
alexira [117]3 years ago
3 0

by the use of elimination method

make all coefficients of subject to be eliminated similar..by multiplying the coefficients with one another

for eqn(i)

5(-10y+9x=-9)

-50y+45x=-45

for eqn(ii)

9(10y+5x=-5)

90y+45x=-45

-50y+45x=-45

90y+45x=-45

...subtract each set from the other...

we get

-140y+0=0

y=0

from eqn(i)

10y+5x=-5

0+5x=-5

x= -1

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Answer:

(a)

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Therefore, suppose that  p = 0.5, then the expected number of flips needed would be 1/0.5  = 2.

Step-by-step explanation:

(a)

Case 1

Imagine that you throw your coin and you get only heads, then you would stop when you get the first tail. So the probability that you stop at the fifth flip would be

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Case 2

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(1-p)^4p

Therefore the probability that you stop at the fifth flip would be

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(b)

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Therefore, suppose that  p = 0.5, then the expected number of flips needed would be 1/0.5  = 2.

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Step-by-step explanation:

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