Points Pand Q lie in plane A. How many lines contain P
1 answer:
Answer:
The correct answer is :
1. Line PQ (One line PQ).
Step-by-step explanation:
The first step to solve this question is to draw the plane A with the points P and Q lying on it.
We know that given two different points there is only one line that contains this two different points.
Let's analyze each option.
''2. Lines PQ and QP''
This option is wrong because there aren't two different lines. In fact it is only one line that can be named line PQ or line QP.
''3. The 2 lines PQ and QP plus another line that does not lie in plane A.''
This option is assuming that exist three lines that contain P and Q. This option is also wrong.
''1. Line PQ''
This option is correct. It will be clarify with the drawing I will attach.
''We can't name them all!''
This option is assuming that exist infinite lines that contain P and Q. This option is wrong.
In the drawing I call the line that contains P and Q as line L.
Given that P and Q lie in plane A necessarily the line L must lie on the plane A.
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Answer:
The combined cost of 1 pound of salmon and 1 pound of swordfish is $16.66
Step-by-step explanation:
Let us assume the cost of 1 pound salmon = $ m
So the cost of 1 pound of 1 pound swordfish cat = $ ( m - 0.20)
Now, the Amount of salmon purchased = 2 1/2 pounds
So, the amount of salmon purchased = 2.5 pounds
Cost of buying 2.5 pounds = 2.5 x ( 1 pound cost)
= 2.5 ( m) = $ 2.5 m ...... (1)
Also, the Amount of swordfish purchased = 1 1/4 pounds
So, the amount of swordfish purchased = 1.25 pounds
Cost of buying 1.25 pounds = 1.25 x ( 1 pound cost of swordfish)
= 1.25 ( m - 0.20) = $ 1.25 m - 0.25 .... (2)
Now, the combined cost paid = $ 31.25
⇒Cost of buying (2.5 pounds salmon + 1.25 pounds swordfish) = $ 31.25
or, 2.5 m + 1.25 m - 0.25 = 31.35 (from (1) and (2))
or, 3.75 m = 31.60
or, m = 31.60/3.75 = 8.43
⇒ m = $8.43
So, the cost of 1 pound salmon = m = $8.43
and the cost of 1 pound swordfish = m - 0.20 = $8.43 - 0.20 = $ 8.23
Hence, the combined cost 1 pound of salmon and 1 pound of swordfish = $8.43 + $ 8.23 = $ 16.66