Answer:
Explanation:
From the equation of Newton's laws of motion
v = u + at where v is final velocity , u is initial velocity and t is time.
150 = 0 + a x 3
a = 50 m / s ²
s = ut + 1/2 at² ; s is distance travelled
s = 50 x 3 + .5 x 50 x 3²
= 150 + 225
= 375 m .
Answer:
It will take 30 seconds to reach the ground, and it will be travelling at 294 m/s when it does so. This means that its average velocity was 147 m/s.
Explanation:

Since the initial velocity of a dropped object is 0, we can make this the equation:


The final velocity can be calculated with the formula:

Once again, since there is no initial velocity:

Since the initial velocity is 0, the average vertical velocity is 294/2=147 m/s.
Hope this helps!
Answer:
contains over 3 billion base pairs
can help explain genetic diseases
composed of 50,000 genes
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Explanation:
JUST TOOK THE TEST ON e d g e n i u t i t y
Hydrogen does not contain any neutrons
Up until the moment the box starts to slip, the static friction is maximized with magnitude <em>f</em>, so that by Newton's second law,
• the net force acting on the box parallel to the ramp is
∑ <em>F</em> = <em>mg</em> sin(<em>α</em>) - <em>f</em> = 0
where <em>mg</em> sin(<em>α</em>) is the magnitude of the parallel component of the box's weight; and
• the net force acting perpendicular to the ramp is
∑ <em>F</em> = <em>n</em> - <em>mg</em> cos(<em>α</em>) = 0
where <em>n</em> is the magnitude of the normal force and <em>mg</em> cos(<em>α</em>) is the magnitude of the perpendicular component of weight.
From the second equation we have
<em>n</em> = <em>mg</em> cos(<em>α</em>)
and <em>f</em> = <em>µn</em> = <em>µmg</em> cos(<em>α</em>), where <em>µ</em> is the coefficient of static friction. Substituting these into the first equation gives us
<em>mg</em> sin(<em>α</em>) = <em>µmg</em> cos(<em>α</em>) ==> <em>µ</em> = tan(<em>α</em>) ==> <em>α</em> = arctan(0.35) ≈ 19.3°