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3 years ago

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Suppose two waves collide, and the temporary combined wave that results is smaller than the original waves. what term best descr

ibes this interaction? (1 point diffraction destructive interference standing wave formation constructive interference

1 answer:

BlackZzzverrR [31]3 years ago

3 0

The collision of the two waves would bring force and that would make the new wave smaller

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The cosmic microwave background essentially looks the same in all directions. This is an example of.

pentagon [3]

In general, all views of the cosmic microwave background are identical. Isotropy is demonstrated by this.

<h3>What exactly is isotropy, for instance?</h3>

The Greek words isos (equal) and tropos, from which the term "isotropy" is derived, mean "uniform in all directions" (way). The material properties of anisotropic materials, such as graphite, differ depending on the direction, in contrast to isotropic materials like glass, which show the same properties in all directions.

There is no "centre" to an isotropic universe, which is another characteristic. The North and South Poles are produced by the rotation of the Earth, giving them a distinctive orientation, but the Universe is visible from every angle. When we think about the Big Bang, which is the origin of the Universe, this is a crucial point.

To know more about cosmic microwave background visit:

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1 year ago

Describe how the three methods of thermal energy transfer may take place within the iguana’s enclosure.

sasho [114]

Answer:

Heat can travel from one place to another in three ways: Conduction, Convection and Radiation. Both conduction and convection require matter to transfer heat. Conduction is the transfer of heat between substances that are in direct contact with each other. Thermal energy is transferred from hot places to cold places by convection. Radiation is a method of heat transfer that does not rely upon any contact between the heat source and the heated object as is the case with conduction and convection. Heat can be transmitted through empty space by thermal radiation often called infrared radiation.

Explanation:

6 0

2 years ago

Read 2 more answers

Find the position of the center of mass of the system of the sun and Jupiter? (Since Jupiter is more massive than the rest of th

8090 [49]

Answer:

$r_{cm} = 0.074 m$ from the position of the center of the Sun

Explanation:

As we know that mass of Sun and Jupiter is given as

$M_s = 1.98 \times 10^{30} kg$

$M_j = 1.89 \times 10^{27} kg$

distance between Sun and Jupiter is given as

$r = 7.78 \times 10^{11} m$

now let the position of Sun is origin and position of Jupiter is given at the position same as the distance between them

so we will have

$r_{cm} = \frac{M_s r_1 + M_j r_2}{M_s + M_j}$

$r_{cm} = \frac{1.98 \times 10^{30} (0) + (1.89 \times 10^{27})(7.78 \times 10^{11})}{1.98 \times 10^{30} + 1.89 \times 10^{27}}$

$r_{cm} = 0.074 m$ from the position of the center of the Sun

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3 years ago

In concave lenses a Distance object appears

JulsSmile [24]

Answer:

it appears to be farther away than it actually is, and therefore smaller then the object itself.

4 0

2 years ago

Andrea's near point is 20.0 cm and her far point is 2.0 m. Her contact lenses are designed so that she can see objects that are

Shalnov [3]

Answer:

the closest distance that she can see an object clearly when she wears her contacts is 22.2 cm

Explanation:

Given the data in the question,

near point = 20 cm

far point = 2 m = 200 cm

Now, for an object that is infinitely far away, the image is at is its far point.

so using the following expression, we can determine the focal length

1/f = 1/i + 1/o

where f is the focal length, i is the image distance and o is the object distance.

here, far point i = 2 m = 200 cm and v is ∞

so we substitute

1/f = 1/(-200 cm) + 1/∞

f = -200 cm

Also, for object at its closest point, the image appear at near point,

so

1/f = 1/i + 1/o

we make o the subject of formula

o = ( i × f ) / ( i - f )

given that near point i = 20 cm

we substitute

o = ( -20 × -200 ) / ( -20 - (-200) )

o = 4000 / 180

o = 22.2 cm

Therefore, the closest distance that she can see an object clearly when she wears her contacts is 22.2 cm

4 0

3 years ago