Answer:
a) F = 2.25 10³ N, b) REPULSIVE.
Explanation:
a) The electric force is given by coulomb's law
F = 
k q1q2 / r2
in this case nso indicate that the two charges have the same value
q₁ = q₂ = 2.5 10⁻⁶ C
Let's reduce the magnitudes to the SI system
r = 0.5 cm (1m / 100cm) = 5 10⁻³ m
let's calculate
F = 
F = 2.25 10³ N
b) In electricity, electric charges of the same sign repel and those of the opposite sign attract
In this exercise, the balls are equal and are rubbed with the same material, for which it acquires charges of the same type, consequently, as the charges are of the same type, they indicate that the negative force is REPULSIVE.
<span>Galileo first studied the Milky Way through his telescope in January, 1610 not 1909. Until his observations, the Milky Way was thought to be a band of wispy whitish clouds passing through the heavens. To Galileo's amazement, instead of seeing just a nebula (the Greek work for cloud) the milky wisps resolved into innumerable tiny stars, so crowded together that, without the aid of a telescope, the light from those stars simply blended together. </span>
Answer:
m = 3.57
Explanation:
Given that,
Sergei uses a lever to lift a heavy rock. He obtains a 2.5m lever and places the fulcrum 0.7m from the rock.
We need to find the ideal mechanical advantage of Sergei's lever.
It is equal to the ratio of resistance arm to the effort arm. In terms of length it is given by :
So, the ideal mechanical advantage of the lever is 3.57.
Explanation:
P.E=MGH
Where m is mass
Where G is Acceleration Due to Gravity
Where h is Height
So the parameters are M = 20kg
G = 9.8m/s
H = 0.5meters
P.E= 20x9.8x0.5
=98J.
So Ans. is A= 98J
Because the two paths are perpendicular, therefore the
target proton's new path must be at 30 degrees from the original
direction.
Using the law of conservation of momentum about the original direction:
m (400 m/s) = m (v1) cos(60) + m (v2) cos(30)
Cancelling m since the two protons have similar mass.
(v1)cos(60) + (v2)cos(30) = 500 m/s ---> 1
Now by using the law conservation of momentum perpendicular to the original
direction:
m (0 m/s) = m (v1) sin(60) – m (v2) sin(30)
Which simplifies to:
(v1)sin(60) - (v2)sin(30) = 0 m/s
v2 = v1 * sin(60) / sin(30) = v1 * sqrt(3) ---> 2
Plugging equation 2 to equation 1:
(v1) (1/2) + (v1 * sqrt(3)) sqrt(3)/2 = 500 m/s
(1/2) (v1) + (3/2) (v1) = 500 m/s
2 (v1) = 500 m/s
v1 = 250 m/s
Thus, from equation 2:
v2 = v1*sqrt(3) = (250 m/s) sqrt(3) = 433.01 m/s
So,
A. The target proton's speed is about 433 m/s
B. The projectile proton's speed is 250 m/s
