A cue ball with mass 170g hits a stationary number 8 ball, which has mass 160g. The cue ball

Physics

1 answer:

forsale [732]3 years ago

3 0

Answer:

0.49 m/s

Explanation:

The law of conservation of linear momentum states that the sum of momentum in a system before and after collision are same. Momentum is a product of mass and velocity of an object hence in this case

$m_cu_c+m_8u_8=m_cv_u+m_8v_8$

Where m represent mass, u and v represent the initial and final velocities respectively, subscripts c and 8 represent cue ball and number 8 ball respectively.

Since number 8 ball is initially at rest, its initial velocity is zero. Replacing mass of cue ball with 170 g while mass of number 8 ball with 160g, then taking final velocity of cue ball as 0.2 m/s and final velocity of 8 ball as 0.3 m/s then we get

$170u_c+160*0=170*0.2+170*0.3\\u_c\approx 0.49 m/s$

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