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Roman55 [17]
3 years ago
13

PLS HELP ASAP (SHOW WORK) LOTS OF POINTS + give thanks if CORRECT

Mathematics
1 answer:
GuDViN [60]3 years ago
3 0
Multiply by two
2/5 x 2/1 = 4/5
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I am just completely lost and am unsure of how to approach this problem.
Anastasy [175]

Answer:

68°

Step-by-step explanation:

As BA⊥BD, so ∠ABD = 90°

also, ∠ABD = ∠CBD + ∠ABC

⇒ 90° = 4x + 52° + 8x - 10°

⇒  12x = 48°

⇒  x = 4°

now,

∠CBD = 4x + 52°

          = 4(4°) + 52°

          = 68°

5 0
3 years ago
Q1: Gabbi purchased a 30 lb. bag of dog food. Gabbi has 3 dogs that each eat 20 ounces of dog food per day. How many days will t
olya-2409 [2.1K]

Answer:

x=8

Step-by-step explanation:

First multiply 30 and 16 to find out how many ounces are in the 30 lb. bag of dog food.

30 x 16=480

Since the 3 dogs eat 20 ounces of food, we can make a equation.

3(20x)=480

20 x 3=60

60x=480

x=8

<u>Final answer</u>

8 days

3 0
3 years ago
a toothpaste shop 500 tubes were sold in August and managers hoping to boost sales 20% in September how many toothpaste tubes mo
Alexus [3.1K]
500×.20=100
500+100=600
600 toothpaste tubes
6 0
3 years ago
(2,-1) <br> y-intercept -3 <br> slope 1/2<br><br> Write an equation with the given info above.
jek_recluse [69]

y-intercept -3  

slope 1/2

is sufficient info with which to write an equation for a straight line:

y = mx + b becomes y = (1/2)x - 3.

You should check this by determining whether or not (2,-1) satisfies this equation.

4 0
3 years ago
Find the GCF of the following numbers:
Maurinko [17]

Answer:

2^53^5

Step-by-step explanation:

So if we compare 2^5 \cdot 3^7 to 2^7 \cdot 3^5, we should see the most amount of factors of 2 that they have in common is 5 and the most amount of factors of 3 that they have in common is 5.

If you aren't sure on the number of factors of 2 and 3 they have in common you could write it all out:

2^53^7=(2)(2)(2)(2)(2)\cdot\text{ }(3)(3)(3)(3)(3)(3)(3

2^73^5=(2)(2)(2)(2)(2)(2)(2)\text{ }(3)(3)(3)(3)(3)

So if I were able to circle each pair of 2's they had in common I would circle 5 pairs.

If were able to circle each pair of 3's they had in common I would circle 5 pairs.

6 0
3 years ago
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