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3 years ago

What is the value of x?

Mathematics

1 answer:

earnstyle [38]3 years ago

8 0

By observing the dash marks on each side we know that this is an equalateral triangle, meaning each angle is 60°. If X=32 then we can tell it does by solving this equation 2(32) - 4 =60 because 2(32)=64 and 64 - 4=60°.
Therefore X=32

Hope this helped!

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Find an equation of variation in which y varies directly as x and y = 60 when x = 0.4. Then find the value of y when x = 2

Nostrana [21]

Answer:

y = 300

Step-by-step explanation:

The equation of variation in which y varies directly as x is written Mathematically as:

y ∝ x

y = k × x

y = kx

Where k = Proportionality Constant

We find k

a) y = 60 when x = 0.4.

60 = 0.4 × k

k = 60/0.4

k = 150

b) find the value of y when x = 2

y = kx

k = 150

Hence,

y = 150 × 2

y = 300

7 0

3 years ago

PLEASE HELP 46 POINTS Use composition of functions to determine whether or not f(x) and g(x) are inverses of each other. Show al

IRISSAK [1]

Remark

The reason you are not getting many replies to this is an uncertainty about f(x). We do not know if you mean f(x) = 2/(x - 6) or f(x) = (2/x) - 6. We'll try it both ways.

First Way f(x) = 2/(x - 6)

f(x = y = 2/(x - 6) Interchange x and y

x = 2 / (y - 6) Multiply both sides by y - 6

x(y - 6) = 2 Divide by x

y - 6 = 2/x Add 6 to both sides.

y = 2/x + 6 Which is close to g(x) but it is not the same thing, even if you use x as a common denominator. That would give you

$\dfrac{6x + 2}{x}$

Second Way: f(x) = (2/x) - 6

f(x) = y = (2/x) - 6 Interchange x and y

x = (2/y) - 6 Add 6 to both sides

x + 6 = 2/y Multiply both sides by y

y(x + 6) = 2 Divide by sides by (x + 6)

y = 2/(x + 6)

Comment

These do not look anything alike so g(x) and f(x) are not inverses.

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3 years ago

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Price of the jar of peanut butter is $2.36 and that of jelly is $1.29.

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3 years ago

Customers arrive at a service facility according to a Poisson process of rate λ customers/hour. Let X(t) be the number of custom

mash [69]

Answer:

Step-by-step explanation:

Given that:

X(t) = be the number of customers that have arrived up to time t.

$W_1,W_2$ ... = the successive arrival times of the customers.

(a)

Then; we can Determine the conditional mean E[W1|X(t)=2] as follows;

$E(W_!|X(t)=2) = \int\limits^t_0 {X} ( \dfrac{d}{dx}P(X(s) \geq 1 |X(t) =2))$

$= 1- P (X(s) \leq 0|X(t) = 2) \\ \\ = 1 - \dfrac{P(X(s) \leq 0 , X(t) =2) }{P(X(t) =2)}$

$= 1 - \dfrac{P(X(s) \leq 0 , 1 \leq X(t)) - X(s) \leq 5 ) }{P(X(t) = 2)}$

$= 1 - \dfrac{P(X(s) \leq 0 ,P((3 \eq X(t)) - X(s) \leq 5 ) }{P(X(t) = 2)}$

Now $P(X(s) \leq 0) = P(X(s) = 0)$

(b) We can Determine the conditional mean E[W3|X(t)=5] as follows;

$E(W_1|X(t) =2 ) = \int\limits^t_0 X (\dfrac{d}{dx}P(X(s) \geq 3 |X(t) =5 )) \\ \\ = 1- P (X(s) \leq 2 | X (t) = 5 ) \\ \\ = 1 - \dfrac{P (X(s) \leq 2, X(t) = 5 }{P(X(t) = 5)} \\ \\ = 1 - \dfrac{P (X(s) \LEQ 2, 3 (t) - X(s) \leq 5 )}{P(X(t) = 2)}$

Now; $P (X(s) \leq 2 ) = P(X(s) = 0 ) + P(X(s) = 1) + P(X(s) = 2)$

So ; the conditional probability density function of $W_2$ given that X(t)=5 is:

$f_{W_2|X(t)=5}}= (W_2|X(t) = 5) \\ \\ =\dfrac{d}{ds}P(W_2 \leq s | X(t) =5 ) \\ \\ = \dfrac{d}{ds}P(X(s) \geq 2 | X(t) = 5)$

7 0

4 years ago

Plz help me Quick l need helpppp

Angelina_Jolie [31]

I’m not really sure but I would have to guess 4.5 because all of the other numbers don’t have decimals

5 0

3 years ago