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Ivenika [448]
3 years ago
9

What is the value of x?

Mathematics
1 answer:
earnstyle [38]3 years ago
8 0
By observing the dash marks on each side we know that this is an equalateral triangle, meaning each angle is 60°. If X=32 then we can tell it does by solving this equation 2(32) - 4 =60 because 2(32)=64 and 64 - 4=60°.
Therefore X=32

Hope this helped!
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Please math , help
Furkat [3]

Answer:

As both the mean and standard deviation are in the desired ranges, the tool passes the technical control.

Step-by-step explanation:

Mean of the batch:

The mean of the batch is the sum of all values divided by the number of items. So

M = \frac{199+204+201+197+195+204+200}{7} = 200

Mean in the desired interval.

Standard deviation:

Square root of the sum of the difference squared between each term and the mean, divided by the number of items. So

S = \sqrt{\frac{(199-200)^2+(204-200)^2+(201-200)^2+(197-200)^2+(195-200)^2+(204-200)^2+(200-200)^2}{7}} = 1.18

As both the mean and standard deviation are in the desired ranges, the tool passes the technical control.

7 0
3 years ago
waiter had 12 tables he was waiting on, with six women and three men at each table. How many total customers did the waiter have
dusya [7]

Answer:

12(6 + 3)

72 + 36

108

108 people

8 0
3 years ago
I need help on all of these please help i’ll mark brainliest!!! <br> -11 + x = 7X - 5
nalin [4]

I don't know what your looking for, so be more specific, but I'm assuming your solving for x, so that's would be

x = -1

8 0
2 years ago
Read 2 more answers
How long will it take for the money to triple? Compounded continuously.
Artemon [7]

The formula for compounded continuously is :

A=Pe^{rt}

Here the Amount triples , so let us say the new amount A=3P

3P=Pe^{rt}

Cancelling P from both sides we get,

3=e^{rt}

Now here we are given rate is 2.75% or 0.0275,

3=e^{0.0275t}

solving for t we get

t=39.95 years

4 0
3 years ago
Determine if the relation is a function. {(0,0), (1,3), (2,5), (3,9)}
kkurt [141]
The relation is a function
5 0
3 years ago
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