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ch4aika [34]
3 years ago
7

Name a chord for the circle.​

Mathematics
1 answer:
kobusy [5.1K]3 years ago
8 0

Answer:

several choices (see below and refer to attached))

Step-by-step explanation:

A chord is a straight line that have BOTH endpoints on the circumference

in our case, we have several chords, just pick one

RN

RP

MN

QN

PQ

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The cost of renting a canoe is $5.25, plus $0.50 per hour for the time that the canoe is out. Which equation could be used to fi
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C = 5.25 + 0.50H

Step-by-step explanation:

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Write an equation of the line passing through the point (4, 2) that is perpendicular to the line 4x + 3y = 7
Dafna1 [17]

Answer:

can you be my new master?

Step-by-step explanation:

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3 years ago
Help on questions 37 and 38 please!
jeka94

Answer:

Step-by-step explanation:

38.

M=\frac{1}{2} (x_{1}+x_{2})\\2M=x_{1}+x_{2}\\x_{1}=2M-x_{2}

37.

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3 years ago
Does anyone know how to solve this?
Charra [1.4K]

Answer:

\frac{\sqrt{2}}{2}

Step-by-step explanation:

This almost looks like the left hand side of the following identity:

\sin(A)\cos(B)-\sin(B)\cos(A)=\sin(A-B) .

Here are similar identities in the same category as the above:

\sin(A)\cos(B)+\sin(B)\cos(A)=\sin(A+B)

\cos(A)\cos(B)-\sin(A)\sin(B)=\cos(A+B)

\cos(A)\cos(B)+\sin(A)\sin(B)=\cos(A-B)

Things to notice: 90-76=14. and 90-59=31.

This means we will possibly want to use the following co-function identities:

\cos(90-A)=\sin(A)

\sin(90-A)=\cos(A)

So let's begin:

\sin(76)\cos(31)-\sin(14)\cos(59)

Applying the co-function identities:

\cos(14)\cos(31)-\sin(14)\sin(31)

Applying one of the difference identities above with cosine:

\cos(31+14)

\cos(45)

45 is a special angle so \cos(45) is something you find off most unit circles in any trigonometry class.

\cos(45)=\frac{\sqrt{2}}{2}

5 0
4 years ago
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