The python program that creates a Bankaccount class for a Bank ATM that is made up of the customers and has a deposit and withdrawal function is given below:
<h3>Python Code</h3>
# Python program to create Bankaccount class
# with both a deposit() and a withdraw() function
class Bank_Account:
def __init__(self):
self.balance=0
print("Hello!!! Welcome to the Deposit & Withdrawal Machine")
def deposit(self):
amount=float(input("Enter amount to be Deposited: "))
self.balance += amount
print("\n Amount Deposited:",amount)
def withdraw(self):
amount = float(input("Enter amount to be Withdrawn: "))
if self.balance>=amount:
self.balance-=amount
print("\n You Withdrew:", amount)
else:
print("\n Insufficient balance ")
def display(self):
print("\n Net Available Balance=",self.balance)
# Driver code
# creating an object of class
s = Bank_Account()
# Calling functions with that class object
deposit()
s.withdraw()
s.display()
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Answer: True A.
Explanation: Every app has or needs a program
By demmaku :v
<span>The client browser requests a page from a Web server.</span>
Answer:
To check if the year comes under each 100th year, lets check if the remainder when dividing with 100 is 0 or not.
Similarly check for 400th year and multiple 0f 4. The following C program describes the function.
#include<stdio.h>
#include<stdbool.h>
bool is_leap_year(int year);
void main()
{
int y;
bool b;
printf("Enter the year in yyyy format: e.g. 1999 \n");
scanf("%d", &y); // taking the input year in yyyy format.
b= is_leap_year(y); //calling the function and returning the output to b
if(b==true)
{
printf("Thae given year is a leap year \n");
}
else
{
printf("The given year is not a leap year \n");
}
}
bool is_leap_year(int year)
{
if(year%100==0) //every 100th year
{
if(year%400==0) //every 400th year
{
return true;
}
else
{
return false;
}
}
if(year%4==0) //is a multiple of 4
{
return true;
}
else
{
return false;
}
}
Explanation:
Output is given as image
Answer:
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