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ehidna [41]
4 years ago
13

A seamstress needs to cut 15 inches pieces of ribbon from a roll of ribbon that is 9 feet in length what is the greatest number

of 15 inches pieces the seamstress can cut from five of these rolls of ribbon
Mathematics
1 answer:
Natali [406]4 years ago
4 0

Answer: 36

Step-by-step explanation:

One roll is of length = 9 feet

1 foot = 12 inches

9 feet = 12 *9 = 108 inches

Since there are 5 rolls

So, total length of 5 rolls = 108 * 5 = 540 inches

Since we are given that A seamstress needs to cut 15-inch pieces of ribbon from a roll of ribbon that is 9 feet in length.

We are supposed to find . What is the greatest number of 15-inch pieces the seamstress can cut from 5 of these rolls of ribbon

So, number of 15-inch pieces the seamstress can cut from 5 of these rolls of ribbon:

Hence the greatest number of 15-inch pieces the seamstress can cut from 5 of these rolls of ribbon is 36

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Help me please please
Ivan
Answer: 11

============================================

Explanation:

Point C is the circumcenter of triangle PQR. This means that we can draw a circle centered at C that goes through points P, Q and R at the same time. This circle has a special name: circumcircle.

The segments PC, RC and QC are all radii, so they are the same length. Pick two of the given expressions and set them equal to one another. Then solve for x

I'm going to pick the expressions for PC and RC

PC = RC
3x+7 = 5x-15
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x = 22/2
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5 0
4 years ago
Help please :/<br> Our teacher wants us to solve a puzzle, but I have no idea what's going on
mote1985 [20]

Answer:

Oh, I done this before

Step-by-step explanation:

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7 0
3 years ago
A fair die is rolled 10 times. Find the expected value of:a) the sum of the numbers in the ten rolls;b) the number of multiples
velikii [3]

Answer:

a) 3.5

b) 3.33

c) 6 - 6\left(\begin{array}{ccc}5\\6\end{array}\right)^{10}

Step-by-step explanation:

As given,

A fair die is rolled 10 times

a)

Expected value of Sum of the number in 10 rolls = \frac{1}{6}(1+2+3+4+5+6) = \frac{21}{6}

                                                                                = 3.5

∴ we get

Expected value of Sum of the number in 10 rolls = 3.5

b)

Ley Y : number of multiples of 3

Y be Binomial

Y - B(n = 10, p = \frac{2}{6} )

Now,

Expected value = E(Y) = np = 10×\frac{2}{6}  = 3.33

c)

Let m = total number of faces in a die

⇒m = 6

As die is roll 10 times

⇒n = 10

Now,

Let Y = number of different faces appears

Now,

Expected value, E(Y) = m - m\left(\begin{array}{ccc}m-1\\m\end{array}\right)^{n}

                                  = 6 - 6\left(\begin{array}{ccc}6-1\\6\end{array}\right)^{10} = 6 - 6\left(\begin{array}{ccc}5\\6\end{array}\right)^{10}

5 0
3 years ago
Find the area of each figure in square units. show your work and explain how you got the answer.​
AfilCa [17]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Suppose that the scores of a history test are normally distributed with a mean of 565 and a standard deviation of 113. a) What p
zvonat [6]

Answer:

15.39% of the scores are less than 450

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 565, \sigma = 113

What percentage of the scores are less than 450?

This is the pvalue of Z when X = 450. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{450 - 565}{113}

Z = -1.02

Z = -1.02 has a pvalue of 0.1539

15.39% of the scores are less than 450

6 0
4 years ago
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