Answer: range= 26, variance= 80 and standard deviation= 8.94
Step-by-step explanation:
Range = highest - lowest
Range = 146 - 120
Range= 26
Let m be mean
M=mean=sum/n
Mean=(120+134+146+127+138+133) / 6
M=798/6
M=133
The standard deviation sample formula:
S.D = sqrt( Summation of |x-m|^2 / n-1)
Let start finding:
|x-m|^2
For 1st: |120-133|^2=169
For 2nd: |134-133|^2=1
For 3rd: |146-133|^2=169
For 4th: |127-133|^2=36
For 5th: |138-133|^2=25
For 6th: |133-133|^2=0
Summation of |x-m|^2 = 400
The standard deviation formula is :
S.D = sqrt( Summation of |x-m|^2 / n-1)
S.D= sqrt(400 / 5)
S.D=sqrt(80)
S.D= 8.94
Variance = (Summation of |x-m|^2 / n-1)
Variance= 400/5
Variance= 80
Answer:
3
Step-by-step explanation:
to find this answer we will then have to do 5 x 2/3
since we our multiplying by a fraction we will then have to change the fraction to a decimal.
2/3 = 0.6
this will then give us the equation of 5 x 0.6
this will give us the sum of 3 jars that had were able to be filled woth marbles.
Answer:
12 + 6 have a good day
Step-by-step explanation:
Answer:
In exercises 3 and 4,write an equation of the line that passes through the given point and is parallel to the given line. 3. (1,3); y=2x-5 4. (-2,1); y= -4x+3 *In exercises 5 and 6, determine which of the lines,if any, are parallel or perpendicular. Explain! 5. line a passes through (-2,3) and (1,-1). Line b passes through (-3,1) and (1,4). Line c passes through (0,2) and (3,-2). 6. Line a: y= -4x +7 Line b: x= 4y+2 Line c: -4y+x=3 *In exercises 7 and 8, write an equation of the line that passes through the given point and is perpendicular to the given line. 7. (2,-3); y= 1/3x -5 8.(6,1); y= -3/5x-5 * In exercises 11-13, determine whether the statement is sometimes,always, or never true. Explain your reasoning! 11. A line with a positive slope and a line with a negative slope are parallel. 12. A vertical line is perpendicular to the x-axis. 13. two lines with the same x-intercept are perpendicular.
Step-by-step explanation:
