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3 years ago

This is the two that go together, but are separate questions

Mathematics

1 answer:

ira [324]3 years ago

5 0

Answers:

Option 1)

6a + 8s = 102

14a + 4s = 150

each adult ticket costs 9 dollars

===================================================

Explanation:

6 adult tickets and 8 student tickets bring in $102, so that means 6a+8s = 102

14 adult tickets and 4 students tickets bring in $150, so 14a+4s = 150

The system of equations is

$\begin{cases}6a+8s = 102\\14a+4s = 150\end{cases}$

If we multiply both sides of the second equation by -2, we get this updated system

$\begin{cases}6a+8s = 102\\-28a-8s = -300\end{cases}$

Add the equations straight down

6a+(-28a) = -22a

8s+(-8s) = 0s = 0 ... the 's' terms go away

102+(-300) = -198

So we end up with the equation -22a = -198 and that solves to a = 9 after dividing both sides by -22.

Each adult ticket costs $9

If you want the value of s, then

6a+8s = 102

6(9)+8s = 102

54 + 8s = 102

8s = 102-54

8s = 48

s = 48/8

s = 6

Meaning each student ticket costs $6

Or you could use the other equation

14a+4s = 150

14(9)+4s = 150

126+4s = 150

4s = 150-126

4s = 24

s = 24/4

s = 6

We get the same value of s

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Step-by-step explanation:

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3 years ago

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3 years ago

(x^2y^3) = (xy^a)^b

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Answer:

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3 years ago

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Anvisha [2.4K]

C. y - 3 = 2/3(x-3)

Nothing much to do here except examine each equation and plug in the numbers to see if it's true.

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Try 3,3
3 + 3 = 3/2(3+3)
6 = 3/2(6). And no need to go further, it's obviously not equal.

b. y - 3 = 3/2(x-3)
Try 3,3
3 - 3 = 3/2(3-3)
0 = 3/2(0). OK. Let's try 6,5
5 - 3 = 3/2(6-3)
2 = 3/2(3)
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c. y - 3 = 2/3(x-3)
Try 3,3
3 - 3 = 2/3(3-3)
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5 - 3 = 2/3(6-3)
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Just to be sure, let's check the next option

d. y + 3 = 2/3(x+3)
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