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yan [13]
3 years ago
6

A box contains 10 red ribbons and 12 blue ribbons. Once a ribbon is picked, it is not replaced. What is the probability of choos

ing a red then a blue ribbon?
Mathematics
1 answer:
lora16 [44]3 years ago
3 0
I belive the answer is 1.
This is because out of 22 ribbon there are 10 which are bue so the probability of blue ribbons is 10/22 and probability of red ribbon is 12/22. So your question was the probability of choosing a red ribbon then a blu ribbon. Because of the word "then" , this means it is simply asking you to add their probablity so after adding 10/22 with 12/22 your answer will come to 22/22 which is equal to 1.
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Evaluate if a = 6 a + a2 =
aniked [119]

Answer:

42

Step-by-step explanation:

6 to the second power is 36+6 is 42.

3 0
3 years ago
Read 2 more answers
Need help ASAP! due soon!!!
-BARSIC- [3]

Answer:

Option B

Step-by-step explanation:

First make x = 4 and y = 3 in the equation y = -1/2x + 5

it should look like 3 = -1/2(4) + 5 now we can solve

   -1/2 * 4 = -2         →      3 = -2 +5

       -2 + 5 = 3         →          3 = 3

5 0
2 years ago
What is the transformation of C(9, 3) when dilated with a scale factor of 1/3,
Harman [31]

The transformation of C(9, 3) when dilated with a scale factor of 1/3, using the point (3, 6) as the center of dilation would be an option B: C'(3,1).

<h3>What is Dilation transformation?</h3>

A dilation transformation is a transformation that changes the size of the original figure but the shape remains unchanged.

If any figure is dilated by a scale factor k with the center of dilation as the origin.

Then the change of transformation in each of the vertices of the figure is given:

(x,y) → (kx, ky)

It is given a point C which is located at C(9,3).

Hence, here k=3

We get:

C(9,3) → C'(9×3,3×3)

C(9,3) → C'(27,9) = C'(3,1)

Hence, the transformation of C(9, 3) when dilated with a scale factor of 1/3, using the point (3, 6) as the center of dilation would be an option B: C'(3,1).

Learn more about dilation;

brainly.com/question/6639345

#SPJ1

3 0
1 year ago
A freight trains departs from one train station to its destination at a constant speed. Suppose the distance the train is from t
marysya [2.9K]

Answer:

Distance = 54 miles (Approx)

Step-by-step explanation:

Given:

Co-ordinate of two point = (0.5,135) and (2,81)

Find:

Distance

Computation:

Distance = √(x1-x2)²+(y1-y2)²

Distance = √(2-0.5)²+(81-135)²

Distance = √2.25 + 2916

Distance = 54 miles (Approx)

6 0
3 years ago
Find an equation in standard form of the parabola passing through these points: (0,-6),(-1,-12),(3,0)
Elan Coil [88]
One form of the equation of a parabola is
y = ax² + bx + c

The curve passes through (0,-6), (-1,-12) and (3,0). Therefore
c = - 6                       (1)
a - b + c = -12            (2)
9a + 3b + c = 0         (3)

Substitute (1) into (2) and into (3).
a - b -6 = -12
a - b = -6                  (4)
9a + 3b - 6 = 0
9a + 3b = 6              (5)

Substitute a = b - 6 from (4) into (5).
9(b - 6) + 3b = 6
12b - 54 = 6
12b = 60
b = 5
a = b - 6 = -1

The equation is
y = -x² + 5x - 6 

Let us use completing the square to write the equation in standard form for a parabola.
y = -[x² - 5x] - 6
   = -[ (x - 2.5)² - 2.5²] - 6
   = -(x - 2.5)² + 6.25 - 6

y = -(x - 2.5)² + 0.25
This is the standdard form of the equation for the parabola.
The vertex us at (2.5, 0.25).
The axis of symmetry is x = 2.5
Because the leading coefficient is -1 (negative), the curve opens downward.
The graph is shown below.

Answer: y = -(x - 2.5)² + 0.25

3 0
3 years ago
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