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tester [92]
3 years ago
7

Find the distance between the point (-3,5,8) and (8,12,2)

Mathematics
1 answer:
Nitella [24]3 years ago
8 0
Learn how to find the distance between two points by using the distance formula, which is an application of the Pythagorean theorem. We can rewrite the Pythagorean theorem as d=√((x_2-x_1)²+(y_2-y_1)²) to find the distance between any two points.
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Which set of numbers can represent the side lengths, in millimeters, of an obtuse triangle?
olga_2 [115]

The answer is actually A.

3 0
3 years ago
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Need answers to 30 and 31
Mice21 [21]

Answer:

C ; A

Step-by-step explanation:

<u>Question 30:</u>

Perimeter is the sum of all sides.

Perimeter for a recatngle can be found with the formula:

2(L+W)

Length is 7

Width is 4

Plug our values in.

2(7+4)

2(11)

22

Answer C

<u>Question 31:</u>

Circumference of a circle can be found with the formula:

πd.

Diameter of the given circle is 6.

Plug it in

6π

Round π to 3.14

6(3.14)

18.84

Answer A

5 0
3 years ago
Can someone help me with this
Naya [18.7K]

Answer:

the answer should be 8.9

you square 12 and square the 8 and subtract them by each other

3 0
3 years ago
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Marshall evaluates the expression 15.3 - 7.9 and gets an answer of 7.4.
d1i1m1o1n [39]

Answer:

C

Step-by-step explanation:

Anything less than 5 rounds down while 5 and anything more rounds up. Therefore...

15.3 rounds to 15

7.9 rounds to 8

7.4 rounds to 7

So, his answer is reasonable.

8 0
2 years ago
Prove that:<br><br>cos20°cos40°cos80°=1/8​
Naya [18.7K]

Answer:

see explanation

Step-by-step explanation:

Using the double angle identity for sine

sin2x = 2sinxcosx

Consider left side

cos20°cos40°cos80°

= \frac{1}{2sin20} (2sin20°cos20°)cos40°cos80°

= \frac{1}{4sin20} (2sin40°cos40°)cos80°

= \frac{1}{4sin20} (sin80°cos80° )

= \frac{1}{8sin20} (2sin80°cos80° )

= \frac{1}{8sin20} . sin160°

= \frac{1}{8sin20} . sin(180 - 20)°

= \frac{1}{8sin20} . sin20°

= \frac{1}{8} = right side , thus proven

7 0
2 years ago
Read 2 more answers
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