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DENIUS [597]
3 years ago
10

The average test score of RSM students in September increased by 10%. In October it increased by another 15%. By what percent di

d the average score on the test increase during the two months? PLEASE HELP I NEED THE ANSWER QUICK
Mathematics
1 answer:
irina [24]3 years ago
4 0

Answer:

26.5%

Step-by-step explanation:

<u>Increasing  Percentages</u>

When sequential percentages increasing are computed, each increase applies to the previous result, instead of the first quantity. That is why sometimes the final results may be confusing. For example, increasing 10% and then 15% will not be the same as increasing a total of 25%.

The average test scores of RSM students first increased by 10%. It means that some quantity C increased by

10C/100=0.1C

Now the average test scores are

C+0.1C=1.1C

A new increasing occurred by 15%, and the previous quantity must be multiplied by 1.15, so the final average test scores are

1.15(1.1C)=1.265C

It means that the total increasing was 100(1.265-1)=26.5\%

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Triangle DEF has vertices D(0,0), E(7,0), and F(3,7).
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Answer:

(3, 1.7)

Step-by-step explanation:

The point at which the vertices of a triangle meet is known as the orthocenter of the triangle. The orthocenter passes through the vertex of the triangle and is perpendicular to the opposite sides.

Two lines are perpendicular if the product of their slopes is -1.

The slope of the line joining D(0,0), F(3,7) is:

m_1=\frac{7-0}{3-0}=\frac{7}{3}

The slope of the line perpendicular to the line joining D and F is -3/7. The orthocenter is perpendicular to the line joining D and F and passes through vertex E(7, 0). The equation is hence:

y-y_1=m(x-x_1)\\\\y-0=-\frac{3}{7} (x-7)\\\\y=-\frac{3}{7}x+3 \ .\ .\ .\ (1)

The slope of the line joining E(7,0), and F(3,7). is:

m_1=\frac{7-0}{3-7}=-\frac{7}{4}

The slope of the line perpendicular to the line joining E and F is 4/7. The orthocenter is perpendicular to the line joining E and F and passes through vertex D(0, 0). The equation is hence:

y-y_1=m(x-x_1)\\\\y-0=\frac{4}{7} (x-0)\\\\y=\frac{4}{7} x\ .\ .\ .\ (2)

The point of intersection of equation 1 and equation 2 is the orthocenter. Solving equation 1 and 2 simultaneously gives:

x = 3, y = 1.7

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