Answer:
Below in bold.
Step-by-step explanation:
Nth term an = a1 + d(n - 1) where a1 = term 1 and d = common difference.
Here a1 = 5 and d = 8-5 = 3.
So an = 5 + 3(n - 1)
15th term a15
= 5 + 3(15 - 1)
= 5 + 42
= 47.
The outlier is 84 and if you removed the outlier from the mean it would decrease.
Answer:
c) 58x2
Step-by-step explanation:
Twice the number 29 is 58
So, 29 is related to 58
Therefore 29*4 = 58*2
Step-by-step explanation:
Explanation:
The trick is to know about the basic idea of sequences and series and also knowing how i cycles.
The powers of i will result in either: i, −1, −i, or 1.
We can regroup i+i2+i3+⋯+i258+i259 into these categories.
We know that i=i5=i9 and so on. The same goes for the other powers of i.
So:
i+i2+i3+⋯+i258+i259
=(i+i5+⋯+i257)+(i2+i6+⋯+i258)+(i3+i7+⋯+i259)+(i4+i8+⋯+i256)
We know that within each of these groups, every term is the same, so we are just counting how much of these are repeating.
=65(i)+65(i2)+65(i3)+64(i4)
From here on out, it's pretty simple. You just evaluate the expression:
=65(i)+65(−1)+65(−i)+64(1)
=65i−65−65i+64
=−65+64
=−1
So,
i+i2+i3+⋯+i258+i259=-1
