Answer:
B) -0.98
Step-by-step explanation:
Correlation coefficient is usually denoted with numbers ranging from 1 to -1. Automatically, this eliminates option C) as our possible answer, since -1.43 is outside the range.
The trend shown in the scatter plot describes a negative relationship because, as the values in the Y-axis decreases, the values at the X-axis increases. The possible correlation coefficient we are likely to get is one that is negative. This eliminates option A and option and option D is our possible correlation coefficient for the scatter plot given since both values are positive.
Option B) -0.98, best represents the correlation coefficient of the given scatter plot. Since the points on the scatter plot seem closely aligned on a straight line, a negative value if -0.98 is mostly the possible one to get.
Hmm, interesting
one way would be to multply it out or set it equal to 11x where x is a whole number (if x is not a whole number, then it is not divisible)
11x=7^6+7^5-7^4
undistribute 7^4
11x=(7^4)(7^2+7^1-1)
11x=(7^4)(49+7-1)
11x=(7^4)(55)
56=5*11
11x=(7^4)(5)(11)
divide by 11
x=5(7^4)
aka, find if 11 is a factor of that number
x=5(7^4)
I think is B sorry if I am worng
Answer:
B
Step-by-step explanation:
Just read and you will see why i say that
Answer:
- m∠A ≈ 53.13°
- m∠B ≈ 73.74°
- m∠C ≈ 53.13°
Step-by-step explanation:
An altitude to AC bisects it and creates two congruent right triangles. This lets you find ∠A = ∠C = arccos(6/10) ≈ 53.13°.
Since the sum of angles of a triangle is 180°, ∠B is the supplement of twice this angle, so is about 73.74°.
m∠A = m∠C ≈ 53.13°
m∠B ≈ 73.74°
_____
The mnemonic SOH CAH TOA reminds you of the relation between the adjacent side, hypotenuse, and trig function of an angle:
Cos = Adjacent/Hypotenuse
If the altitude from B bisects AC at X, triangle AXB is a right triangle with side AX adjacent to the angle A, and side AB as the hypotenuse. AX is half of AC, so has length 12/2 = 6, telling you the cosine of angle A is AX/AB = 6/10.
A diagram does not have to be sophisticated to be useful.
