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salantis [7]
3 years ago
12

Samuel and Zander together have $392. Samuel has six times as much money as Zander. How much does each have? Please help! Quick

will give brainliest to whoever giving the best answer!​
Mathematics
1 answer:
Shalnov [3]3 years ago
3 0

Answer:

Samuel has $336 and Zander has $56

Step-by-step explanation:

Samuel = 6x because he has 6 times Zander

Zander = x

Together they have 392

6x + x = 392

7x = 392

Divide both sides by 7

x = 56

Samuel = 6 x 56 = 336

Zander = 56

336 + 56 = 392

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Answer:

Step-by-step explanation:

So we are assuming only the times listed  count toward telling us how long the game was, so you just add the three numbers together.  155, 175 and 30

4 0
3 years ago
It’s multiple choice , please help me !
ICE Princess25 [194]
Answer: a, c, e explanation: I did that test and got 100%
3 0
3 years ago
When Marika bought her house she paid 80% of the purchase price of the house with a loan. She paid the remaining 49,400 of the p
Maurinko [17]

Let

x-----> the purchase price of the house

we know that

1) Marika paid 80\% of the purchase price of the house with a loan

2) Marika paid the remaining \$49,400 of the purchase price with her savings

3) \$49,400 represent the 20\% of the purchase price

so

0.20x=49,400

Solve for x

Divide by 0.20 both sides

0.20x/0.20=49,400/0.20

x=247,000

therefore

<u>the answer is</u>

the purchase price of the house is \$247,000

3 0
3 years ago
We are conducting a hypothesis test to determine if fewer than 80% of ST 311 Hybrid students complete all modules before class.
Juli2301 [7.4K]

Answer:

z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124  

Null hypothesis:p\geq 0.8  

Alternative hypothesis:p < 0.8  

Since is a left tailed test the p value would be:  

p_v =P(Z  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis:p\leq 0.8  

Alternative hypothesis:p > 0.8

p_v =P(Z>2.124)=0.013  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation  

n=110 represent the random sample taken

X=97 represent the students who completed the modules before class

\hat p=\frac{97}{110}=0.882 estimated proportion of students who completed the modules before class

p_o=0.8 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v{/tex} represent the p value (variable of interest)  2) Concepts and formulas to use  We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.8 or 80%:  Null hypothesis:[tex]p\geq 0.8  

Alternative hypothesis:p < 0.8  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis:p\leq 0.8  

Alternative hypothesis:p > 0.8

p_v =P(Z>2.124)=0.013  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis.

5 0
4 years ago
4(1+.5m)=7m<br>what is m?<br>​
RUDIKE [14]
M= 4/5 or the alternative form for m can be 0.8
3 0
3 years ago
Read 2 more answers
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