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3 years ago

Please help quickly :) thanks

Mathematics

1 answer:

juin [17]3 years ago

8 0

The missing part is the proof ... hope it helped thank you you welcome have a frat day thanks bye adios amigo q to balls bin en too visa much's gracious yew me la peals pot too Ajax thanks yes what ever loll

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Plot the following ordered pairs on a graph and then determine whether or not the points represent a function.

Alex777 [14]

The answer is :

YES: These points represent a function because none of the vertical lines I drew passed through more than one point.

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3 years ago

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What is the value of x in the right triangle shown? 25 cm 7 cm

finlep [7]

Answer:

x = 24

Step-by-step explanation:

a^2 + b^2 = c^2

7^2 + b^2 = 25^2

49 + b^2 = 625

-49 -49

b^2 = 576

square root them

b = 24, or x = 24

Hope this helped! Have a nice day! Plz mark as brainliest!!!

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3 years ago

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Please help!!!

morpeh [17]

Y would be 5. Brainliest please!!!

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3 years ago

Solve the equation for all real values of x. cosxtanx - 2 cos x=-1

IceJOKER [234]

Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

Step-by-step explanation:

Here we have , $cosxtanx - 2 cos^2 x=-1$ . Let's solve :

⇒ $cosxtanx - 2 cos^2 x=-1$

⇒ $cosx(\frac{sinx}{cosx}) - 2 cos^2 x=-1$

⇒ $sinx = 2 cos^2 x-1$

⇒ $sinx = 2 (1-sin^2x)-1$

⇒ $sinx = 1-2sin^2x$

⇒ $2sin^2x+sinx-1=0$

By quadratic formula :

⇒ $sinx = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

⇒ $sinx = \frac{-1 \pm \sqrt{1^2-4(2)(-1)} }{2(2)}$

⇒ $sinx = \frac{-1 \pm3}{4}$

⇒ $sinx = \frac{1}{2} , sinx =-1$

⇒ $sinx = sin\frac{\pi}{6} , sinx = sin\frac{3\pi}{2}$

⇒ $x=\frac{\pi}{6} , x=\frac{3\pi}{2}$

But at $x=\frac{3\pi}{2}$ we have equation undefined as $cos\frac{3\pi}{2}=0$ . Hence only solution is :

⇒ $x=\frac{\pi}{6}$

Since , $sin(\pi -x)=sinx$

⇒ $x=\pi -\frac{\pi}{6} = \frac{5\pi}{6}$

Now , General Solution is given by :

⇒ $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$

Therefore , Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

3 0

3 years ago

A student writes the equation for a line that has a slope of -6 and passes through the point (2, –8).

Ilia_Sergeevich [38]

Answer:

The error in the students work is

y -(-8) + 8 = -6x + 12 + 8

subtracting a negative is adding

y+8

They should subtract 8 from each side instead of adding 8 to each side

Step-by-step explanation:

We can use point slope form since we are given a point and the slope

y-y1 = m( x-x1)

y--8 = -6(x-2)

y+8 = -6(x-2)

Distribute the -6

y+8 = -6x+12

Subtract 8 from each side

y+8-8 = -6x+12-8

y = -6x+4

The error in the students work is

y -(-8) + 8 = -6x + 12 + 8

subtracting a negative is adding

y+8

They should subtract 8 from each side instead of adding 8 to each side

4 0

3 years ago

Read 2 more answers