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3 years ago

5

How many servings of 3/4 cups are in 32/2cups

1 answer:

NARA [144]3 years ago

8 0

Answer: 3/64

Step-by-step explanation: I think you ask 3/4 divided by 32/2 if you are the answer is 3/64. How to divided is first simplify the expression, if possible, by canceling the common factors. But if your asking me to do 32/2 divided by 3/4 the answer is 64/3 if you want it to be an improper fraction but if you want it to be a mixed fraction it would be 21 1/3. How to divided is first simplify the expression, if possible, by canceling the common factors.

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A woman takes 12 equal-sized steps. She walks a total of 10 yards

kiruha [24]

Answer:

Each step is 30 inches

Step-by-step explanation: One yard is 36 inches. 10 yards is 360 inches.

360 divided by 12 is 30.

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2 years ago

Find the degree of the following polynomial:<br> 7xy223 + 8y5 – 3x4 + 4

Vika [28.1K]

Answer:

224

Step-by-step explanation:

polynomial degree:224

leading term:7x^223

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3 years ago

What is 7% of 39? <br><br><br> Thank you for your help.

iVinArrow [24]

Answer:

W=2.73

Step-by-step explanation:

Is means equals and of means multiply

W = 7% of 39

Change to decimal form

W = .07 * 39

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8 0

3 years ago

Read 2 more answers

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

3 years ago

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sergiy2304 [10]

Answer:

The first one 6 second 10

just got it right :)

4 0

3 years ago

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