Answer:
part a: 1/2, two red, probability is 1/2
part b: 450, 150 times 3 =450, hope it helps
please make me brainliest
The circumference of a circle of diameter 13 m is 13π m, about 40.82 m.
(40.82 m)/(2.5 m) = 16.328
16 may be the best approximation of the number of pieces Malia will need. 17 pieces will make a barrier that is longer (larger diameter) than is needed.
The answer is 6 or 8 which ever one u feel comfortable with
Answer:
x = 3/4 + (3 sqrt(5))/4 or x = 3/4 - (3 sqrt(5))/4
Step-by-step explanation:
Solve for x over the real numbers:
8 x^2 - 12 x - 23 = -5
Divide both sides by 8:
x^2 - (3 x)/2 - 23/8 = -5/8
Add 23/8 to both sides:
x^2 - (3 x)/2 = 9/4
Add 9/16 to both sides:
x^2 - (3 x)/2 + 9/16 = 45/16
Write the left hand side as a square:
(x - 3/4)^2 = 45/16
Take the square root of both sides:
x - 3/4 = (3 sqrt(5))/4 or x - 3/4 = -(3 sqrt(5))/4
Add 3/4 to both sides:
x = 3/4 + (3 sqrt(5))/4 or x - 3/4 = -(3 sqrt(5))/4
Add 3/4 to both sides:
Answer: x = 3/4 + (3 sqrt(5))/4 or x = 3/4 - (3 sqrt(5))/4
Answer: B. Jonesville is growing linearly and Smithville is growing exponentially.
Step-by-step explanation:
Linear growth :
- Population grow by a constant amount after each time period.
- The rate of change of dependent variable with respect to independent variable is a constant.
- It is represented by line on graph.
- Equation for linear growth :
, c = initial value and m is the rate of change of y with respect to x.
Exponential growth :
- Population grow by a constant ratio .
- It is represented by a curve on graph.
- Equation for exponential growth :
, a = initial value and r is rate of growth ( in decimal ) and x is time period.
Given : Jonesville's population grows by 170 people per year.
i.e .Population grow by a constant amount per year.
⇒ Jonesville is growing linearly.
The population of smithville grows by 7% per year.
i.e. Population grow by a constant ratio.
⇒Smithville is growing exponentially.
Hence, the true statement is "B. Jonesville is growing linearly and Smithville is growing exponentially."