Answer:
a₄₂ = 107
Step-by-step explanation:
The nth term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given a₂₇ = 66 , then
a₁ + 26d = 66 , that is
- 12 + 26d = 66 ( add 12 to both sides )
26d = 78 ( divide both sides by 26 )
d = 3
Then
a₄₂ = - 16 + (41 × 3) = - 12 + 123 = 111
5b + 29 ≤ -25 is the translation of the phrase "the sum of a number times 5 and 29 is at most -25"
<h3>How to translate an English phrase into an algebraic equation?</h3>
Given the phrase in the question;
The sum of a number times 5 and 29 is at most -25.
First, we translate;
Let the unknown number represented by b.
- A number times 5 ⇒ b × 5 ⇒ 5b
- Sum ⇒ 5b + 29
- Inequality sign for at most -25 ⇒ less than or equal to ⇒ ≤ -25
Now we combine the terms;
5b + 29 ≤ -25
We can go and solve for the unknown number.
5b + 29 ≤ -25
Subtract 29 from both sides
5b + 29 - 29 ≤ -25 - 29
5b ≤ -25 - 29
5b ≤ -54
b ≤ -54/5
Therefore, the translation of the phrase is 5b + 29 ≤ -25.
Learn more about inequality here: brainly.com/question/20383699
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Answer:
( 
, 0 )
Step-by-step explanation:
To find the x- intercepts let y = 0, that is
2x² + 3x - 2 = 0
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 2 × - 2 = - 4 and sum = + 3
The factors are + 4 and - 1
Use these factors to split the x- term
2x² + 4x - x - 2 = 0 ( factor the first/second and third/fourth terms )
2x(x + 2) - 1 (x + 2) ← factor out (x + 2) from each term
(x + 2)(2x - 1) = 0
Equate each factor to zero and solve for x
x + 2 = 0 ⇒ x = - 2
2x - 1 = 0 ⇒ 2x = 1 ⇒ x =
The x- intercepts are (- 2, 0 ), ( , 0 )
Answer:
120
240
Step-by-step explanation:
We call the length of first part x
Length of second part = y
In the first scenario, it took the tortoise 110 sec to walk the first part and crawl the second.
So,
We have this equation,
x/4 + y/3 = 110
We take the LCM
(3x + 4y)/12 = 110
When we cross multiply
3x + 4y = 110x12
3x + 4y = 1320 ----- equation 1
For scenario 2
x/3 + y/4 = 100
When we take the LCM
(4x + 3y)/12 = 100
We cross multiply
4x + 3y = 100x12
4x + 3y = 1200 ------ equation 2
We now have two equations and we will solve for x and y using simultaneous linear equation.
3x + 4y = 1320 ----- 1
4x + 3y = 1200 ----- 2
We subtract equation 2 from 1 to get
- x + y = 120
We make y subject
y = x + 120 ----- 3
We put the value of y in equation 3 into equation 1
3x + 4(x + 120) = 1320
3x + 4x + 480 = 1320
7x + 480 = 1320
7x = 1320-480
7x = 840
We divide through by 7
x = 840/7
x = 120
We put value of x in equation 3
y = x + 120
y = 120 + 120
y = 240
120 and 240 are the lengths of the 2 parts of the journey.
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