The solution of the equation is (2, 1).
x=2 and y=1
<h3>What do you meant by equation?</h3>
A mathematical assertion that two expressions are equal is known as equating. It can be expressed as either an identity, in which case the variables can take on any value, or a conditional equation, in which case the variables can only have specific values (roots).
<h3>
According to the given information:</h3>
We have two options for finding the answer. The first is to solve the equations via term elimination:
x + 3y = 5 ..............1
x - 3y = -1 ...............2
2x = 4 ..............3
With the equation, we can determine x. (3)
x = 4/2
x = 2
To determine y, we may now swap out x=2 in equation (1).
x + 3y = 5
2 + 3y = 5
3y = 3
y = 1
We've discovered x and y now.
x=2
y=1
The second method involves removing x from equation 1.
x + 3y = 5
x = 5 - 3y
In the equation right now, we may substitute x = 5 - 3y......... (2)
x - 3y = -1
(5 - 3y) - 3y = -1
5 - 6y = -1
6y = -6
y = 1
Currently, we can change y=1 in equations (1), (2), or (4) to find x.
We'll apply the equation (1)
x + 3y = 5
x + 3(1) = 5
x + 3 = 5
x = 2
The two variants x = 2 and y = 1 have allowed us to confirm this.
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