$8,900 at 4.5% compounded semiannually for 5 years
2 answers:
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Answer:
100 trees should be planted per acre to maximize the total yield (15000 apples per acre)
Step-by-step explanation:
<u>Functions </u>
Expressing some quantities in terms of other(s) comes in handy to understand the behavior of the situations often modeled by those functions.
Our problem tells us about the smith family orchard, where the average yield per apple tree is 150 apples when the number of trees per acre is 100 (or less). But the average yield per tree decreases when more than 100 trees are planted. The rate of decrease is 1 for each additional tree is planted
Let's call x the number of trees planted per acre in a single growing season. We have two conditions when modeling: when x is less than 100, the average yield per apple tree (Ay) is (fixed) 150.
When x is more than 100:
The upper limit is 150 because it would mean the Average yield is zero and no apples are to be harvested
Part 1
We are asked what happens if the number of trees per acre was doubled, but we don't know what the original number was. Let's make it x=60
If x=60, then we must use the first function, and
Ay(60)=150
The yield per acre will be 150*60=9000 apples
If we doubled x to 120, we would have to use the second function
Ay(120)=150-x=30
The yield per acre will be 30*120=3600 apples
Note that doubling the number of trees would make the production decrease
If we started with x=30, then
Ay(30)=150, and we would have 150*30=4500 apples per acre
We already know that for x=60 (the double of 30), our production will be 9000 apples per acre
This shows us that in some cases, increasing the number of trees is beneficial and in other cases, it is not
Part 2
The total yield is computed as
Y(x)=x.Ay(x)
This function will be different depending on the value of x
To find the maximum total yield we take the first derivative
The first expression has no variable, so the total yield must be evaluated in the endpoints
Y(0)=0
Y(100)=15000
Now, the second expression contains variable, it will be set to 0 to find the critical point
150-2x=0
x=75
x is outside of the boundaries, we cannot find the maximum in this interval
Answer: 100 trees should be planted per acre to maximize the total yield (15000 apples per acre)
<h3>Answer:</h3>
- 8 pieces
- 3/8 foot
a) Let n represent the number of 1 7/8 ft pieces. Then we have ...
... 16 1/2 ft = n × (1 7/8 ft)
We can find n by dividing this equation by 1 7/8.
... (16 1/2)/(1 7/8) = n = (132/8)/(15/8) = 132/15
... n = 8 12/15 = 8 4/5
The integer number of pieces that can be cut is 8 pieces.
b) The length of the left-over piece is 4/5 of the full length of a piece, so is ...
... (4/5) × (15/8 ft) = 12/8 ft
We want to divide this into 4 equal lengths, so each of those lengths will be 1/4 of the length of the left-over:
... (1/4) × (12/8 ft) = 3/8 ft
_____
<em>Comment on arithmetic with fractions</em>
This problem is easier if you <em>convert the mixed numbers to improper fractions</em>. This is done by expressing the integer as a number of fractional parts, then adding the fraction part of the mixed number:
... a + b/c = (a×c/c) + b/c = (ac +b)/c
Division with fractions is taught a couple of different ways. One way you can do it is to "invert and multiply". That is, you multiply the numerator fraction by the reciprocal of the denominator fraction:
... (a/b)/(c/d) = (a/b)×(d/c)
Another way you can do the division is to express each of the numerator and denominator fractions over the same denominator. Then the quotient is the ratio of numerators.
... (a/c)/(b/c) = a/b
This is the method we used here. Effectively, we converted 16 1/2 to 16 4/8 then to (16×8 +4)/8 = 132/8. Then the numerator and denominator fractions both had denominators of 8, so (132/8)/(15/8) = 132/15. This fraction can be reduced by removing a factor of 3 from numerator and denominator to give ...
... 132/15 = 44/5 = 8 4/5